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Find total number of distinct years from a string in C++ Program
In this tutorial, we are going to write a program that finds distinct years in the given string. Let's see some examples. We are assuming the date format is DD/MM/YYYY.
Input − Sample example with dates 01/11/2020, 02/12/2020, and 03/10/2019.
Output − 2
We have two distinct years in the given text 2020 and 2019.
We are going to use regex to extract all dates from the given string. If you are not familiar with regex in C++, go through this tutorial.
Let's jump into solving the problem.
Initialize the text.
Write the regex to extract dates from the text.
Initialize an empty unordered set.
Iterate over the dates and add year to the unordered set to find unique years.
Print the length of the set.
Example
Let's see the code.
#include <iostream>
#include <bits/stdc++.h>
#include <regex>
using namespace std;
int uniqueYearsCount(string text) {
// regex
regex date_regex("[0-9]{1,2}/[0-9]{1,2}/[0-9]{4}");
smatch matching_date;
// set to store unique dates
unordered_set<string> dates;
// finding all dates
while (regex_search(text, matching_date, date_regex)) {
string date = matching_date[0];
dates.insert(date.substr(date.size() - 4));
text = matching_date.suffix();
}
return dates.size();
}
int main() {
string text = "Sample example with dates 01/11/2020, 02/12/2020, and 03/10/2019.";
cout << uniqueYearsCount(text) << endl;
return 0;
}Output
If run the above code, then you will get the following result.
2
We can get dates in a different formats. If you get dates in different formats, then update the regex appropriately.
Conclusion
If you have any queries in the tutorial, mention them in the comment section.
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