# Find the number of spectators standing in the stadium at time t in Python

There are n number of spectators in the stadium, and they are labeled from 1 to n. Now follow these cases −

• At time t1, the first spectator stands.

• At time t2, the second spectator stands.

• At time tk, the k-th spectator stands.

• At time tk + 1, the (k + 1)-th spectator stands and the first spectator sits.

• At time tk + 2, the (k + 2)-th spectator stands and the second spectator sits.

• At time tn, the n-th spectator stands and the (n – k)-th spectator sits.

• At time tn + 1, the (n + 1 – k)-th spectator sits.

• At time tn + k, the n-th spectator sits.

So, if the input is like n = 11, k = 6, t = 4, then the output will be 4 as at time t1, 1st spectator stands, then at time t2, 2nd spectator stands after that at time t3, 3rd spectator stands, and finally at time t4, 4th spectator stands. In this way the result is 4 as there are 4 spectators standing in total.

To solve this, we will follow these steps −

• if t <= k, then

• return t

• otherwise when t <= n, then

• return k

• otherwise,

• res := t - n

• res := k - res

• return res

## Example

Let us see the following implementation to get better understanding −

Live Demo

def how_many_stand(n, k, t) :
if (t <= k) :
return t
elif (t <= n) :
return k
else :
res = t - n
res = k - res
return res
n = 11
k = 6
t = 4
print(how_many_stand(n, k, t))

## Input

11, 6, 4

## Output

4

Updated on: 27-Aug-2020

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