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In this article we are required to find that number from the list which occurs odd number of times in the given list. We are also required to use the Lambda function and the reduce function.

We design a function where the reduce function is used by applying the Lambda function to check if the element is present odd number of times.

from functools import reduce def oddcount(i): print(reduce(lambda x, y: x ^ y, i)) listA = [12,34,12,12,34] print("Given list:\n",listA) print("The element present odd number of times:") oddcount(listA)

Running the above code gives us the following result −

Given list: [12, 34, 12, 12, 34] The element present odd number of times: 12

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