Find Numbers with Even Number of Digits in Python
Suppose we have a list of numbers. We have to count the numbers that has even number of digit count. So if the array is like [12,345,2,6,7896], the output will be 2, as 12 and 7896 has even number of digits
To solve this, we will follow these steps −
- Take the list and convert each integer into string
- if the length of string is even, then increase count and finally return the count value
Example
Let us see the following implementation to get better understanding −
Live Demo
class Solution(object):
def findNumbers(self, nums):
str_num = map(str, nums)
count = 0
for s in str_num:
if len(s) % 2 == 0:
count += 1
return count
ob1 = Solution()
print(ob1.findNumbers([12,345,2,6,7897]))
Input
[12,345,2,6,7897]
Output
2
Published on 20-Jan-2020 11:28:30
