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Splitting an array based on its first value - JavaScript
Suppose we have an array of arrays of numbers like this −
const arr = [[1, 45], [1, 34], [1, 49], [2, 34], [4, 78], [2, 67], [4, 65]];
Each subarray is bound to contain strictly two elements. We are required to write a function that constructs a new array where all second elements of the subarrays that have similar first value are grouped together.
Therefore, for the array above, the output should look like −
const output = [ [45, 34, 49], [34, 67], [78, 65] ];
We can make use of the Array.prototype.reduce() method that takes help of a Map() to construct the required array.
Example
Following is the code −
const arr = [[1, 45], [1, 34], [1, 49], [2, 34], [4, 78], [2, 67], [4, 65]];
const constructSimilarArray = (arr = []) => {
const creds = arr.reduce((acc, val) => {
const { map, res } = acc;
if(!map.has(val[0])){
map.set(val[0], res.push([val[1]]) - 1);
}else{
res[map.get(val[0])].push(val[1]);
};
return { map, res };
}, {
map: new Map(),
res: []
});
return creds.res;
};
console.log(constructSimilarArray(arr));Output
This will produce the following output in console −
[ [ 45, 34, 49 ], [ 34, 67 ], [ 78, 65 ] ]
Updated on: 18-Sep-2020
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