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Filling diagonal to make the sum of every row, column and diagonal equal of 3×3 matrix using c++
Suppose we have one 3x3 matrix, whose diagonal elements are empty at first. We have to fill the diagonal such that the sum of a row, column and diagonal will be the same. Suppose a matrix is like −
After filling, it will be −
Suppose the diagonal elements are x, y, z. The values will be −
- x = (M[2, 3] + M[3, 2])/ 2
- z = (M[1, 2] + M[2, 1])/ 2
- y = (x + z)/2
Example
#include<iostream>
using namespace std;
void displayMatrix(int matrix[3][3]) {
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++)
cout << matrix[i][j] << " ";
cout << endl;
}
}
void fillDiagonal(int matrix[3][3]) {
matrix[0][0] = (matrix[1][2] + matrix[2][1]) / 2;
matrix[2][2] = (matrix[0][1] + matrix[1][0]) / 2;
matrix[1][1] = (matrix[0][0] + matrix[2][2]) / 2;
cout << "Final Matrix" << endl;
displayMatrix(matrix);
}
int main() {
int matrix[3][3] = {
{ 0, 3, 6 },
{ 5, 0, 5 },
{ 4, 7, 0 }};
cout << "Given Matrix" << endl;
displayMatrix(matrix);
fillDiagonal(matrix);
}Output
Given Matrix 0 3 6 5 0 5 4 7 0 Final Matrix 6 3 6 5 5 5 4 7 4
Updated on: 29-Oct-2019
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