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Factorize the expression $28a^2 + 14a^2b^2 - 21a^4$.
The given expression is $28a^2 + 14a^2b^2 - 21a^4$.
We have to factorize the expression $28a^2 + 14a^2b^2 - 21a^4$.
A common factor of two or more numbers is a factor that is shared by the numbers. The greatest common factor (GCF) of those numbers is found by finding all common factors of the numbers and selecting the largest one.
The terms in the given expression are $28a^2, 14a^2b^2$ and $- 21a^4$.
The numerical coefficient of $28a^2$ is $28$
The numerical coefficient of $14a^2b^2$ is $14$
The numerical coefficient of $- 21a^4$ is $21$
GCF of $28, 14$ and $21$ is $7$
The common variable in the given terms is $a$.
The power of $a$ in $28a^2$ is $2$
The power of $a$ in $14a^2b^2$ is $2$
The power of $a$ in $- 21a^4$ is $4$
The monomial of common literals with the smallest power is $a^2$
$28a^2=7\times a^2 \times (4)$
$14a^2b^2=7\times a^2 \times (2b^2)$
$- 21a^4=7\times a^2 \times (-3a^2)$
$28a^2 + 14a^2b^2 - 21a^4=7a^2(4+2b^2-3a^2)$
Hence, the given expression can be factorized as $7a^2(4+2b^2-3a^2)$.
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