- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Factorize the expression $4(xy+1)^2-9(x-1)^2$.
Given:
The given algebraic expression is $4(xy+1)^2-9(x-1)^2$.
To do:
We have to factorize the expression $4(xy+1)^2-9(x-1)^2$.
Solution:
Factorizing algebraic expressions:
Factorizing an algebraic expression implies writing the expression as a product of two or more factors. Factorization is the reverse of distribution.
An algebraic expression is factored completely when it is written as a product of prime factors.
$4(xy+1)^2-9(x-1)^2$ can be written as,
$4(xy+1)^2-9(x-1)^2=[2(xy+1)]^2-[3(x-1)]^2$ [Since $4=2^2, 9=3^2$]
Here, we can observe that the given expression is a difference of two squares. So, by using the formula $a^2-b^2=(a+b)(a-b)$, we can factorize the given expression.
Therefore,
$4(xy+1)^2-9(x-1)^2=[2(xy+1)]^2-[3(x-1)]^2$
$4(xy+1)^2-9(x-1)^2=[2(xy+1)+3(x-1)][2(xy+1)-3(x-1)]$
$4(xy+1)^2-9(x-1)^2=[2xy+2+3x-3][2xy+2-3x+3]$
$4(xy+1)^2-9(x-1)^2=(2xy+3x-1)(2xy-3x+5)$
Hence, the given expression can be factorized as $(2xy+3x-1)(2xy-3x+5)$.
To Continue Learning Please Login
Login with Google