Explain the stack by using linked list in C language

CServer Side ProgrammingProgramming

Stack over flow and stack under flow can be avoided by allocating memory dynamically.

Operations carried out under stack in C programming language are as follows −

  • Push
  • Pop

Push

Following is the basic implementation of a linked list −

&item = 10
newnode = (node*) malloc (sizeof (node));
newnode ->data = item;
newnode ->link = NULL;
newnode ->link = start;
start = newnode;

pop

The syntax is as follows −

Syntax

if (start = = NULL)
printf("Deletion is not possible.List is empty")
else{
   temp = start;
   start = start link;
   free (temp);
}

Program

Following is the C program for stack by using linked lists −

#include <stdio.h>
#include <stdlib.h>
struct node{
   int info;
   struct node *ptr;
}*top,*top1,*temp;
int topelement();
void push(int data);
void pop();
void empty();
void display();
void destroy();
void stack_count();
void create();
int count = 0;
void main(){
   int no, ch, e;
   printf("\n 1 - Push");
   printf("\n 2 - Pop");
   printf("\n 3 - Top");
   printf("\n 4 - Empty");
   printf("\n 5 - Exit");
   printf("\n 6 - Display");
   printf("\n 7 - Stack Count");
   printf("\n 8 - Destroy stack");
   create();
   while (1){
      printf("\n Enter choice : ");
      scanf("%d", &ch);
      switch (ch){
         case 1:
            printf("Enter element : ");
         scanf("%d", &no);
         push(no);
         break;
         case 2:
            pop();
         break;
         case 3:
            if (top == NULL)
               printf("stack is empty");
         else{
            e = topelement();
            printf("\n Top element : %d", e);
         }
         break;
         case 4:
            empty();
         break;
         case 5:
            exit(0);
         case 6:
            display();
         break;
         case 7:
            stack_count();
         break;
         case 8:
            destroy();
         break;
            default :
         printf(" wrong choice:Try again ");
         break;
      }
   }
}
//empty stack
void create(){
   top = NULL;
}
void stack_count(){
   printf("\n no: of elements in stack : %d", count);
}
//push data
void push(int data){
   if (top == NULL){
      top =(struct node *)malloc(1*sizeof(struct node));
      top->ptr = NULL;
      top->info = data;
   }
   else{
      temp =(struct node *)malloc(1*sizeof(struct node));
      temp->ptr = top;
      temp->info = data;
      top = temp;
   }
   count++;
}
void display(){
   top1 = top;
   if (top1 == NULL){
      printf("empty stack");
      return;
   }
   while (top1 != NULL){
      printf("%d ", top1->info);
      top1 = top1->ptr;
   }
}
void pop(){
   top1 = top;
   if (top1 == NULL){
      printf("\n error");
      return;
   }
   else
      top1 = top1->ptr;
      printf("\n Popped value : %d", top->info);
      free(top);
      top = top1;
      count--;
   }
   int topelement(){
      return(top->info);
   }
   //check stack empty or not
   void empty(){
      if (top == NULL)
         printf("\n empty stack");
      else
         printf("\n stack not empty with %d values", count);
      }
      void destroy(){
         top1 = top;
      while (top1 != NULL){
         top1 = top->ptr;
         free(top);
      top = top1;
      top1 = top1->ptr;
   }
   free(top1);
   top = NULL;
   printf("\n all are destroyed");
   count = 0;
}

Output

When the above program is executed, it produces the following result −

1 - Push
2 - Pop
3 - Top
4 - Empty
5 - Exit
6 - Display
7 - Stack Count
8 - Destroy stack
Enter choice: 1
Enter element: 23
Enter choice: 1
Enter element: 45
Enter choice: 1
Enter element: 56
Enter choice: 2
Popped value: 56
Enter choice: 6
45 23
Enter choice: 8
all are destroyed
Enter choice: 6
empty stack
Enter choice: 5
raja
Published on 26-Mar-2021 06:44:45
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