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Display highest amount from corresponding duplicate ids in MySQL
To display highest amount from corresponding duplicate ids, use MAX() along with GROUP BY clause −
mysql> create table DemoTable2003 ( CustomerId int, Amount int ); Query OK, 0 rows affected (0.65 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable2003 values(101,560); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable2003 values(102,1080); Query OK, 1 row affected (0.15 sec) mysql> insert into DemoTable2003 values(101,570); Query OK, 1 row affected (0.16 sec) mysql> insert into DemoTable2003 values(102,870); Query OK, 1 row affected (0.21 sec) mysql> insert into DemoTable2003 values(101,460); Query OK, 1 row affected (0.12 sec)
Display all records from the table using select statement −
mysql> select * from DemoTable2003;
This will produce the following output −
+------------+--------+ | CustomerId | Amount | +------------+--------+ | 101 | 560 | | 102 | 1080 | | 101 | 570 | | 102 | 870 | | 101 | 460 | +------------+--------+ 5 rows in set (0.00 sec)
Here is the query to display highest amount from corresponding duplicate ids −
mysql> select CustomerId, max(Amount) from DemoTable2003 group by CustomerId;
This will produce the following output −
+------------+-------------+ | CustomerId | max(Amount) | +------------+-------------+ | 101 | 570 | | 102 | 1080 | +------------+-------------+ 2 rows in set (0.00 sec)
Updated on: 02-Jan-2020
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