Cube each element in a Numpy array

To cube each element in an array., element-wise, use the numpy.power() method in Python. Here, the 1st parameter is the base and the 2nd exponents. Since, we want the cube, the exponent is 3.

Raise each base in x1 to the positionally-corresponding power in x2. x1 and x2 must be broadcastable to the same shape. An integer type raised to a negative integer power will raise a ValueError. Negative values raised to a non-integral value will return nan. To get complex results, cast the input to complex, or specify the dtype to be complex.

Steps

At first, import the required library −

import numpy as np

Create an array −

arr = np.array([5, 10, 25, 7, 9])

Display the array −

print("Array...\n", arr)

Get the type of the array −

print("\nOur Array type...\n", arr.dtype)

Get the dimensions of the Array −

print("\nOur Array Dimension...\n",arr.ndim)

Get the shape of the Array −

print("\nOur Array Shape...\n",arr.shape)

To cube each element in an array., element-wise, use the numpy.power() method in Python. Here, the 1st parameter is the base and the 2nd exponents. Since, we want the cube, the exponent is 3 −

print("\nResult...\n",np.power(arr, 3))

Example

import numpy as np

# Create an array
arr = np.array([5, 10, 25, 7, 9])

# Display the array
print("Array...\n", arr)

# Get the type of the array
print("\nOur Array type...\n", arr.dtype)

# Get the dimensions of the Array
print("\nOur Array Dimension...\n",arr.ndim)

# Get the shape of the Array
print("\nOur Array Shape...\n",arr.shape)

# To cube each element in an array., element-wise, use the numpy.power() method in Python
# Here, the 1st parameter is the base and the 2nd exponents
# Since, we want the cube, the exponent is 3
print("\nResult...\n",np.power(arr, 3))

Output

Array...
[ 5 10 25 7 9]

Our Array type...
int64

Our Array Dimension...
1

Our Array Shape...
(5,)

Result...
[ 125 1000 15625 343 729]

AmitDiwan

Updated on 07-Feb-2022 13:10:52

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