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C++ program to Find Sum of Natural Numbers using Recursion
The natural numbers are the positive integers starting from 1.
The sequence of natural numbers is −
1, 2, 3, 4, 5, 6, 7, 8, 9, 10……
The program to find the sum of first n natural numbers using recursion is as follows.
Example
#include <iostream>
using namespace std;
int sum(int n) {
if(n == 0)
return n;
else
return n + sum(n-1);
}
int main() {
int n = 10;
cout<<"Sum of first "<<n<<" natural numbers is "<<sum(n);
return 0;
}Output
Sum of first 10 natural numbers is 55
In the above program, the function sum() is a recursive function. If n is 0, it returns 0 as the sum of the first 0 natural numbers is 0. If n is more than 0, then sum recursively calls itself itself with the value n-1 and eventually returns the sum of n, n-1, n-2…...2,1. The code snippet that demonstrates this is as follows.
int sum(int n) {
if(n == 0)
return n;
else
return n + sum(n-1);
}In the function main(), the sum of the first n natural numbers is displayed using cout. This can be seen as follows −
cout<<"Sum of first "<<n<<" natural numbers is "<<sum(n);
Updated on: 24-Jun-2020
2K+ Views
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