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C++ Program to Calculate Sum of Natural Numbers
The natural numbers are the positive integers starting from 1.
The sequence of natural numbers is −
1, 2, 3, 4, 5, 6, 7, 8, 9, 10……
Sum of the first n natural numbers can be calculated using the for loop or the formula.
Programs specifying both of these methods are given as follows −
Sum of Natural Numbers Using for loop.
The program to calculate the sum of n natural numbers using for loop is given as follows.
Example
#include<iostream> using namespace std; int main() { int n=5, sum=0, i; for(i=1;i<=n;i++) sum=sum+i; cout<<"Sum of first "<<n<<" natural numbers is "<<sum; return 0; }
Output
Sum of first 5 natural numbers is 15
In the above program, a for loop is run from 1 to n. In each iteration of the loop, the value of i is added to the sum. So, the sum of the first n natural numbers is obtained. This is demonstrated by the following code snippet.
for(i=1;i<=n;i++) sum=sum+i;
Sum of Natural Numbers using Formula
The formula to find the sum of first n natural numbers is as follows.
sum = n(n+1)/2
The program to calculate the sum of n natural numbers using the above formula is given as follows.
Example
#include<iostream> using namespace std; int main() { int n=5, sum; sum = n*(n+1)/2; cout<<"Sum of first "<<n<<" natural numbers is "<<sum; return 0; }
Output
Sum of first 5 natural numbers is 15
In the above program, the sum of the first n natural numbers is calculated using the formula. Then this value is displayed. This is demonstrated by the following code snippet.
sum = n*(n+1)/2; cout<<"Sum of first "<<n<<" natural numbers is "<<sum;