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C++ code to find screen size with n pixels
Suppose we have a number n. In a display there will be n pixels. We have to find the size of rectangular display. The rule is like below −
The number of rows (a) does not exceed number of columns (b) [a <= b]
The difference between b - a is as minimum as possible
So, if the input is like n = 12, then the output will be (3, 4)
Steps
To solve this, we will follow these steps −
i := square root of n while n mod i is non-zero, do: (decrease i by 1) return (i, n / i)
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
void solve(int n){
int i = sqrt(n);
while (n % i)
i--;
cout << i << ", " << n / i;
}
int main(){
int n = 12;
solve(n);
}Input
12
Output
3, 4
Updated on: 30-Mar-2022
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