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C++ code to find array from given array with conditions
Suppose we have an array A with n elements. There is another hidden array B of size n. The elements can be negative or positive. For each index i in range 1 to n, following operations will be performed −
Set A[i] as 0 initially
Then add B[i] to A[i], subtract B[i+1], then add B[i+2] and so on
We have to find the array B.
So, if the input is like A = [6, -4, 8, -2, 3], then the output will be [2, 4, 6, 1, 3]
Steps
To solve this, we will follow these steps −
for initialize i := 0, when i < size of A, update (increase i by 1), do: print (A[i] + A[i + 1])
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
void solve(vector<int> A){
for (int i = 0; i < A.size(); i++)
cout << A[i] + A[i + 1] << ", ";
}
int main(){
vector<int> A = { 6, -4, 8, -2, 3 };
solve(A);
}Input
{ 6, -4, 8, -2, 3 }Output
2, 4, 6, 1, 3,
Updated on: 29-Mar-2022
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