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Counting rings in letters using JavaScript
Problem
We are required to write a JavaScript function that takes in a string of English alphabets.Our function should count the number of rings present in the string.
O', 'b', 'p', 'e', 'A', etc. all have one rings whereas 'B' has 2
Example
Following is the code −
const str = 'some random text string';
function countRings(str){
const rings = ['A', 'D', 'O', 'P', 'Q', 'R', 'a', 'b', 'd', 'e', 'g', 'o', 'p', 'q'];
const twoRings = ['B'];
let score = 0;
str.split('').map(x => rings.includes(x)
? score++
: twoRings.includes(x)
? score = score + 2
: x
);
return score;
}
console.log(countRings(str));Output
7
Updated on: 17-Apr-2021
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