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Counting specific digits used in squares of numbers using JavaScript
Problem
We are required to write a JavaScript function that takes in an integer n (n >= 0) and a digit d (0 <= d <= 9)
Our function should square all numbers k (0 <= k <= n) between 0 and n and count the numbers of digits d used in the writing of all the k**2.
Example
Following is the code −
const n = 25;
const d = 1;
const countDigits = (n, d) => {
let k = 0, count = 0;
d = d.toString();
while (k <= n) {
let a = 0;
let s = (k*k).toString();
for(let i = 0; i < s.length; i++)
if(s[i] == d)
a++;
if (a > 0) {
count += a;
};
k++;
};
return count;
};
console.log(countDigits(n, d));Output
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Updated on: 17-Apr-2021
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