Count ways to reach a score using 1 and 2 with no consecutive 2s in C++

C++Server Side ProgrammingProgramming

Given a score of runs. The goal is to reach that score in a way that the batsman can take either 1 or 2 runs only in a single ball. The restriction is that no 2 runs can be taken consecutively. For example, to reach the given score 6, one can take runs like: 1+2+1+2 but not 2+2+1+1 or any other way with two consecutive 2’s.

For Example

Input

score=4

Output

Count of ways to reach a score using 1 and 2 with no consecutive 2s are: 4

Explanation

The ways in which we can reach the score 4 in following ways:
1+1+1+1, 1+1+2, 1+2+1, 2+1+1

Input

score=5

Output

Count of ways to reach a score using 1 and 2 with no consecutive 2s are: 6

Explanation

The ways in which we can reach the score 6 in following ways:
1+1+1+1+1, 2+1+1+1, 1+2+1+1 , 1+1+2+1, 1+1+1+2, 2+1+2

Approach used in the below program is as follows

In this approach we will use a flag to mark that previous score was two or not, in case it was 2 we will cover the score with the next run as 1 else 2.

  • Take an integer variable score.

  • Take flag variable check = false initially.

  • Function ways_reach_score(int score, bool check) tells the count of ways to reach a score using 1 and 2 with no consecutive 2s.

  • Take the initial count as 0.

  • If the score is 0 return 0.

  • If the check is false means previous run was 1, so in case current score is greater then ways will be count = ways_reach_score(score − 1, false) + ways_reach_score(score − 2, true).

  • Otherwise the previous run was 2, so the consequent run will be 1 only so ways will be ways_reach_score(score − 1, false).

  • At the end we will get total ways in count.

  • Return count as result.

Example

 Live Demo

#include <bits/stdc++.h>
using namespace std;
int ways_reach_score(int score, bool check){
   int count = 0;
   if (score == 0){
      return 1;
   }
   if (check == false && score > 1){
      count += ways_reach_score(score − 1, false) + ways_reach_score(score − 2, true);
   } else {
      count += ways_reach_score(score − 1, false);
   }
   return count;
}
int main(){
   int score = 4;
   bool check = false;
   cout<<"Count of ways to reach a score using 1 and 2 with no consecutive 2s are: "<<ways_reach_score(score, check);
   return 0;
}

Output

If we run the above code it will generate the following output −

Count of ways to reach a score using 1 and 2 with no consecutive 2s are: 4
raja
Published on 05-Jan-2021 06:19:25
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