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Count how many times the given digital clock shows identical digits in C++
Suppose we have a digital clock of type HH:MM. Which shows the time in hours and minutes only. We are given a number of hours and minutes as input. The goal is to count the number of times all digits are the same. H=M.
This happens 3 times a day, first at 00:00 midnight, then at 11:11 and last at 22:22. As time is represented in 24 hour format.
Input
Input: 12 hours 22 minutes.
Output
2
Explanation − For times 00:00 and 11:11. Twice in 12 hours.
Input
Input: 48 hours 22 minutes.
Output
5
Explanation − For times 00:00 and 11:11, 22:22 .
Approach used in the below program is as follows
- Variables hours and minutes store the input.
- Function countIdentical(int hours, int minutes) takes minutes and hours and return count of no. of times all HH;MM digits are the same.
- For 00:00 initialize count as 1.
- For each hour as 11 and 22 and minutes as 11 and 22 increment count by 1.
- Return the result after the loop ends.
- Count is the desired result.
- Print the count.
Example
// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
// examples- 11:11 11hrs 11 mins, 22:22
int countIdentical(int hours, int minutes){
// Initialized to 1 because of 00:00
int i, count=1;
// For double digit hours
for (i = 0; i <= 99 && i < hours; i = i + 11) {
// Double digit minutes
if ((i % 10) < minutes)
count++;
}
return count;
}
int main(){
int hours = 48;
int minutes = 22;
cout <<"Times when all digits are identical in HH:MM :"
<< countIdentical(hours, minutes);
return 0;
}Output
Times when all digits are identical in HH:MM : 6
Updated on: 03-Aug-2020
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