Count all possible paths between two vertices in C++

C++Server Side ProgrammingProgramming

In this tutorial, we will be discussing a program to find the number of paths between two vertices.

For this we will be provided with a directed graph. Our task is to find the number of paths possible between two given vertices.


using namespace std;
//constructing a directed graph
class Graph{
   int V;
   list<int> *adj;
   void countPathsUtil(int, int, bool [],int &);
      Graph(int V);
      void addEdge(int u, int v);
      int countPaths(int s, int d);
Graph::Graph(int V){
   this->V = V;
   adj = new list<int>[V];
void Graph::addEdge(int u, int v){
int Graph::countPaths(int s, int d){
   //marking all the vertices
   // as not visited
   bool *visited = new bool[V];
   memset(visited, false, sizeof(visited));
   int pathCount = 0;
   countPathsUtil(s, d, visited, pathCount);
   return pathCount;
void Graph::countPathsUtil(int u, int d, bool visited[],
int &pathCount){
   visited[u] = true;
   //if current vertex is same as destination,
   // then increment count
   if (u == d)
      //if current vertex is not destination
   else {
      list<int>::iterator i;
      for (i = adj[u].begin(); i != adj[u].end(); ++i)
         if (!visited[*i])
            countPathsUtil(*i, d, visited,pathCount);
   visited[u] = false;
int main(){
   Graph g(4);
   g.addEdge(0, 1);
   g.addEdge(0, 2);
   g.addEdge(0, 3);
   g.addEdge(2, 0);
   g.addEdge(2, 1);
   g.addEdge(1, 3);
   int s = 2, d = 3;
   cout << g.countPaths(s, d);
   return 0;


Published on 10-Feb-2020 12:05:23