Consider the following information in respect of four objects A, B, C and D:

Object	Density$(kg/m^3)$	Volume$(m^3)$	Mass$(kg)$
A		2	4000
B	8000	4
C	2000		1000
D		4	2000

Which object would float on water?
(a) A
(b) B
(c) C
(d) D"

In the given table, Mass of object A $=4000\ kg$

Volume of object A $=2\ m^3$

Therefore, the density of A $=\frac{mass}{density}$

$=\frac{4000\ kg}{2\ m^3}$

$=2000\ kg/m^3$

Similarly, density of object C $=\frac{2000\ kg}{4\ m^3}=500\ kg/m^3$

Now we can arrange the densities of objects A, B, C, and D as below in the table:

Here we observe that the density of the object D is less than that of the water. So Object D will float in water.

Therefore, option (d) is correct.

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Updated on: 10-Oct-2022

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