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# Collatz sequence in Python

Suppose we have a positve integer n, we have to find the length of its Collatz sequence. As we know Collatz sequence is generated sequentially where n = n/2 when n is even otherwise n = 3n + 1. And this sequence ends when n = 1.

So, if the input is like n = 13, then the output will be 10 as [13, 40, 20, 10, 5, 16, 8, 4, 2, 1] these is the sequence.

To solve this, we will follow these steps −

- if num is same as 0, then
- return 0

- length := 1
- while num is not same as 1, do
- num :=(num / 2) when num mod 2 is 0 otherwise (3 * num + 1)
- length := length + 1

- return length

Let us see the following implementation to get better understanding −

## Example

class Solution: def solve(self, num): if num == 0: return 0 length = 1 while num != 1: num = (num / 2) if num % 2 == 0 else (3 * num + 1) length += 1 return length ob = Solution() print(ob.solve(13))

## Input

13

## Output

10

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