# Check if it is possible to rearrange rectangles in a non-ascending order of breadths in Python

PythonServer Side ProgrammingProgramming

Suppose we have a list of rectangles represented using its length and breadth. We can rotate any rectangle by 90 degrees so after rotating, the breadth will become length and vice-versa. We have to check whether we can sort the rectangles in non-increasing order of breadth.

So, if the input is like rects = [[4, 5], [5, 7], [4, 6]], then the output will be True as the breadths are [5,7,6] now if we rotate last two rectangles then breadths will be [5,5,4] which is in non-increasing way.

To solve this, we will follow these steps −

• m := 99999
• for i in range 0 to size of rect, do
• if maximum of length and breadth of ith rectangle <= m, then
• m := maximum of length and breadth of ith rectangle
• otherwise when minimum of length and breadth of ith rectangle <= m
• m := minimum of length and breadth of ith rectangle
• otherwise,
• return False
• return True

## Example

Let us see the following implementation to get better understanding −

Live Demo

def solve(rect):
m = 99999
for i in range(len(rect)):
if max(rect[i], rect[i]) <= m:
m = max(rect[i], rect[i])
elif min(rect[i], rect[i]) <= m:
m = min(rect[i], rect[i])
else:
return False
return True
rects = [[4, 5], [5, 7], [4, 6]]
print(solve(rects))

## Input

[[4, 5], [5, 7], [4, 6]]

## Output

True