Check if it is possible to create a polygon with a given angle in Python

Suppose we have an angle a. We have to check whether we can make a regular polygon where all angles are same as a or not.

So, if the input is like a = 120, then the output will be True the pentagon has all angles same as 120°. As we know

$$Interior Angle(a)=\frac{180\times(n-2)}{n}\begin{bmatrix} n=number of sides of polygon\end{bmatrix}$$ $$¿n=\frac{360}{180-a}$$

So if n is integer then this is forming a regular polygon.

To solve this, we will follow these steps −

• sides := 360 /(180 - a)
• if sides has no fractional part, then
  • return True
• return False

Example

Let us see the following implementation to get better understanding −

 Live Demo

def solve(a) :
   sides = 360 / (180 - a)
   if sides == int(sides) :
      return True
   return False
a = 120
print (solve(a))

Input

120

Output

True