Suppose we have an array of numbers called nums, where all elements are unique. We have to check whether nums is almost sorted or not. As we know an array is almost sorted when any of its elements can occur at a maximum of 1 distance away from its original position in the sorted array.
So, if the input is like nums = [10, 30, 20, 40], then the output will be True as 10 is placed at its original place and all other elements are at max one place away from their actual position.
To solve this, we will follow these steps −
Let us see the following implementation to get better understanding −
def solve(nums): i = 0 while i < len(nums) - 1: if nums[i] > nums[i + 1]: nums[i], nums[i + 1] = nums[i + 1], nums[i] i += 1 i += 1 for i in range(len(nums) - 1): if nums[i] > nums[i + 1]: return False return True nums = [10, 30, 20, 40] print(solve(nums))
[10, 30, 20, 40]