Check if elements of Linked List are present in pair in Python

Suppose we have a singly linked list. We have to check whether each element in the given linked list is present in a pair, in other words all elements occur even no. of times.

So, if the input is like list = [2,5,5,2,3,3], then the output will be True.

To solve this, we will follow these steps −

• xor_res := 0, current_node := head of linked list
• while current_node is not null, do
  • xor_res := xor_res XOR value of current_node
  • current_node := next of current_node
• return False when xor_res is non-zero otherwise True

Example

Let us see the following implementation to get better understanding −

 Live Demo

class ListNode:
   def __init__(self, data, next = None):
      self.val = data
      self.next = next
def make_list(elements):
   head = ListNode(elements[0])
   for element in elements[1:]:
      ptr = head
      while ptr.next:
         ptr = ptr.next
      ptr.next = ListNode(element)
   return head
def solve(head):
   xor_res = 0
   current_node = head
   while current_node != None:
      xor_res = xor_res ^ current_node.val
      current_node = current_node.next
   return False if xor_res else True
head = make_list([2,5,5,2,3,3])
print(solve(head))

Input

[2,5,5,2,3,3]

Output

True