# Check if characters of a given string can be rearranged to form a palindrome in Python

Suppose we have a string s, we have to check whether characters of the given string can be shuffled to make a palindrome or not.

So, if the input is like s = "raaecrc", then the output will be True as we can rearrange this to "racecar" which is a palindrome.

To solve this, we will follow these steps −

• freq := a map to store all characters and their frequencies in s
• odd_count := 0
• for each element i in the list of all values of freq, do
• if i is odd, then
• odd_count := odd_count + 1
• if odd_count > 1, then
• return False
• return True

Let us see the following implementation to get better understanding −

## Example

Live Demo

from collections import defaultdict
def solve(st) :
freq = defaultdict(int)
for char in st :
freq[char] += 1
odd_count = 0
for i in freq.values():
if i % 2 == 1:
odd_count = odd_count + 1
if odd_count > 1:
return False
return True
s = "raaecrc"
print(solve(s))

## Input

"raaecrc"

## Output

True