# Check if an array of 1s and 2s can be divided into 2 parts with equal sum in Python

Suppose we have an array nums which only stores 1 and 2 in it. We have to check whether the array can be divided into two different parts such that sum of elements in each part is same.

So, if the input is like nums = [1, 1, 2, 2, 2], then the output will be True as we can divide this array like [1, 1, 2] and [2, 2] the sum of each part is 4.

To solve this, we will follow these steps −

• total := 0, one_count := 0
• total := sum of all elements of nums
• one_count := count of 1s in nums
• if total is even, then
• return False
• if integer part of (total / 2) is even, then
• return True
• if one_count > 0, then
• return True
• otherwise,
• return False

Let us see the following implementation to get better understanding −

## Example

Live Demo

def solve(nums):
total = 0
one_count = 0
total = sum(nums)
one_count = nums.count(1)
if total % 2:
return False
if (total // 2) % 2 == 0:
return True
if one_count > 0:
return True
else:
return False
nums = [1, 1, 2, 2, 2]
print(solve(nums))

## Input

[1, 1, 2, 2, 2]

## Output

True

Updated on: 30-Dec-2020

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