Check if a string follows a^n b^n pattern or not in Python

PythonServer Side ProgrammingProgramming

Suppose we have a string s we have to check whether the string is following the pattern a^nb^n or not. This is actually a string when n = 3, the string will be "aaabbb".

So, if the input is like s = "aaaaabbbbb", then the output will be True as this follows a^5b^5.

To solve this, we will follow these steps −

  • size := size of s
  • for i in range 0 to size - 1, do
    • if s[i] is not same as 'a', then
      • come out from loop
  • if i * 2 is not same as size, then
    • return False
  • for j in range i to size - 1, do
    • if s[j] is not same as 'b', then
      • return False
  • return True

Let us see the following implementation to get better understanding −

Example

 Live Demo

def solve(s):
   size = len(s)
   for i in range(size):
      if s[i] != 'a':
         break
   if i * 2 != size:
      return False
   for j in range(i, size):
      if s[j] != 'b':
         return False
   return True
s = "aaaaabbbbb"
print(solve(s))

Input

"aaaaabbbbb"

Output

True
raja
Published on 29-Dec-2020 13:14:02
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