Check if a string can become empty by recursively deleting a given sub-string in Python

Suppose we have two strings s and t. We can delete t from s any number of times. And t appears only once at a time. We have to check whether s can become empty by removing t as many times as required.

So, if the input is like s = "pipipinnn" t = "pin", then the output will be True as we can remove "pin" from "pipipinnn", then we will get "pipinn", again remove "pin" to get string "pin", then remove it to make it empty.

To solve this, we will follow these steps −

• while size of s > 0, do
  • position := starting index of t in s
  • if position is not in the s, then
    • come out from the loop
  • s := remove t from s one time
• return true when size of s is same as 0 otherwise false

Let us see the following implementation to get better understanding −

Example

 Live Demo

def solve(s, t):
   while len(s) > 0:
      position = s.find(t)
      if position == -1:
         break
      s = s.replace(t, "", 1)
   return len(s) == 0
s = "pipipinnn"
t = "pin"
print(solve(s, t))

Input

"pipipinnn", "pin"

Output

True

Arnab Chakraborty

Updated on: 29-Dec-2020

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