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Here we will see, if a number has adjacent set bits in its binary representation. Suppose the number 12 has two consecutive 1s (12 = 1100).

To check this type of number, the idea is very simple. We will shift the number 1 bit, then do bitwise AND. If the bitwise AND result is non-zero, then there must be some consecutive 1s.

#include <iostream> using namespace std; bool hasConsecutiveOnes(int n) { if((n & (n >> 1)) == 1){ return true; }else{ return false; } } int main() { int num = 67; //1000011 if(hasConsecutiveOnes(num)){ cout << "Has Consecutive 1s"; }else{ cout << "Has No Consecutive 1s"; } }

Has Consecutive 1s

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