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Check if a large number is divisible by 9 or not in C++
Here we will see how to check a number is divisible by 9 or not. In this case the number is very large number. So we put the number as string.
A number will be divisible by 9, if the sum of digits is divisible by 9.
Example
#include <bits/stdc++.h>
using namespace std;
bool isDiv3(string num){
int n = num.length();
long sum = accumulate(begin(num), end(num), 0) - '0' * n;
if(sum % 9 == 0)
return true;
return false;
}
int main() {
string num = "630720";
if(isDiv3(num)){
cout << "Divisible";
} else {
cout << "Not Divisible";
}
}Output
Divisible
Updated on: 27-Sep-2019
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