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Here we will see how to check a number is divisible by 3 or not. In this case the number is very large number. So we put the number as string.

A number will be divisible by 3, if the sum of digits is divisible by 3.

#include <bits/stdc++.h> using namespace std; bool isDiv3(string num){ int n = num.length(); long sum = accumulate(begin(num), end(num), 0) - '0' * n; if(sum % 3 == 0) return true; return false; } int main() { string num = "3635883959606670431112222"; if(isDiv3(num)){ cout << "Divisible"; } else { cout << "Not Divisible"; } }

Divisible

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