Calculate the number of neutrons present in the nucleus of an element X which is represented as ³¹X₁₅

Academic Chemistry NCERT Class 9

Mass number (A) = No. of protons (Z) + No. of neutrons

Given, mass number = 31

No. of protons = 15

No. of protons (Z) + No. of neutrons = 31

No. of neutrons = 31 – number of protons

No. of neutrons = 31 – 15 = 16.

Hence, the No. of neutrons =16.

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Updated on: 19-Jan-2023

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