# C program to find type of array entered by the user.

## Problem

Write a C Program to find the array type which we need to check, whether the given elements in an array are even numbers or odd numbers or combination of both.

## Solution

So, user has to enter an array of integers, then, display the type of the array.

Example 1 − Input: 5 3 1, Output: odd array.

Example 2 − Input: 2 4 6 8, Output: even array.

Example 3 − Input: 1 2 3 4 5, Output: mixed array.

## Algorithm

Refer an algorithm given below to find the array type entered by the user.

Step 1 − Read the size of array at runtime.

Step 2 − Input the array elements.

Step 3 − If all the elements of the array are odd, Then, print "Odd".

Step 4 − If all the elements of the array are even, Then, print "Even".

Step 5 − Else, print "Mixed".

## Example

Following is the C program to find the array type entered by the user −

Live Demo

#include<stdio.h>
int main(){
int n;
printf("enter no of elements:");
scanf("%d",&n);
int arr[n];
int i;
int odd = 0, even = 0;
printf("enter the elements into an array:");
for(i = 0; i < n; i++){
scanf("%d",&arr[i]);
}
for(i = 0; i < n; i++){
if(arr[i] % 2 == 1)
odd++;
if(arr[i] % 2 == 0)
even++;
}
if(odd == n)
printf("Odd Array");
else if(even == n)
printf("Even Array");
else
printf("Mixed Array");
return 0;
}

## Output

When the above program is executed, it produces the following output −

Run 1:
enter no of elements:5
enter the elements into an array:
2 4 8 10 12
Even Array
Run 2:
enter no of elements:5
enter the elements into an array:
1
23
45
16
68
Mixed Array

Updated on: 26-Mar-2021

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