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C# Program to display the Factors of the Entered Number
Firstly, let us enter the number.
Console.WriteLine("Enter a Number"); n = int.Parse(Console.ReadLine());
Now loop through and find the mod of the entered number with i = 1 that increments after every iteration. If its 0, then print it, since it would be our factor.
for (i= 1; i <= n; i++) { if (n % i == 0) { Console.WriteLine(i); } }
Let us see the complete code to find factors of a number.
Example
using System; namespace Demo { class MyApplication { static void Main(string[] args) { int n, i; Console.WriteLine("Enter a Number"); n = int.Parse(Console.ReadLine()); Console.WriteLine("Factors = "); for (i= 1; i <= n; i++) { if (n % i == 0) { Console.WriteLine(i); } } Console.ReadLine(); } } }
Output
Enter a Number
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