- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

A greedy algorithm is an algorithm used to find an optimal solution for the given problem. greedy algorithm works by finding locally optimal solutions ( optimal solution for a part of the problem) of each part so show the Global optimal solution could be found.

In this problem, we will use a *greedy algorithm to find the minimum number of coins/ notes that could makeup to the given sum.* For this we will take under consideration all the valid coins or notes i.e. denominations of { 1, 2, 5, 10, 20, 50 , 100, 200 , 500 ,2000 }. And we need to return the number of these coins/notes we will need to make up to the sum.

Let’s take a few examples to understand the context better −

Input : 1231 Output : 7

**Explanation** − We will need two Rs 500 notes, two Rs 100 notes, one Rs 20 note, one Rs 10 note and one Re 1 coin. That sums to 2+2+1+1+1 = 7

Input : 2150 Output : 3

Explanation − We will need one Rs 2000 note, one Rs 100 note, and one Rs 50 note.

To solve this problem using a greedy algorithm, we will find the which is the largest denomination that can be used. then we will subtract the largest denomination from the sum and again do the same process until the sum becomes zero.

Input: sum, Initialise the coins = 0 Step 1: Find the largest denomination that can be used i.e. smaller than sum. Step 2: Add denomination two coins and subtract it from the Sum Step 3: Repeat step 2 until the sum becomes 0. Step 4: Print each value in coins.

#include <bits/stdc++.h> using namespace std; int notes[] = { 1, 2, 5, 10, 20, 50, 100, 200, 500, 2000 }; int n = sizeof(notes) / sizeof(notes[0]); void minchange(int sum){ vector<int> coins; for (int i = n - 1; i >= 0; i--) { while (sum >= notes[i]) { sum -= notes[i]; coins.push_back(notes[i]); } } for (int i = 0; i < coins.size(); i++) cout << coins[i] << "\t"; } int main(){ int n = 3253; cout << "The minimum number of coins/notes that sum up " << n << " is \t "; minchange(n); return 0; }

The minimum number of coins/notes that sum up 3253 is 2000 500 500 200 50 2 1

- Related Questions & Answers
- Find out the minimum number of coins required to pay total amount in C++
- C++ Program to Perform Greedy Coloring
- C Program for Minimum number of jumps to reach the end
- C Program to Find the minimum sum of factors of a number?
- Python Program for Find minimum sum of factors of number
- Minimum number of coins that make a given value
- Program to find number of coins needed to make the changes with given set of coins in Python
- Program to find number of combinations of coins to reach target in Python
- C Program for Reversal algorithm for array rotation
- C Program for Naive algorithm for Pattern Searching
- C Program for KMP Algorithm for Pattern Searching
- Program to find maximum number of coins we can collect in Python
- Program to find maximum number of coins we can get using Python
- Find minimum sum of factors of number using C++.
- Program to find minimum number of groups in communication towers in C++?\n

Advertisements