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Articles by sudhir sharma
Page 43 of 98
Sum of the Series 1/(1*2) + 1/(2*3) + 1/(3*4) + 1/(4*5) + ... in C++
In this problem, we are given a number n which is the nth term of the series 1/(1*2) + 1/(2*3) +…+ 1/(n*(n+1)). Our task is to create a program to find the sum of the series.Let’s take an example to understand the problem, Input n = 3Output 0.75Explanation − sum = 1/(1*2) + 1/(2*3) + 1/(3*4) = ½ + ⅙+ 1/12 = (6+2+1)/12 = 9/12 = ¾ = 0.75A simple solution to the problem is using the loop. And commuting value for each element of the series. Then add them to the sum value.AlgorithmInitialize sum = 0 Step 1: Iterate from i = ...
Read MoreSum of the series 2 + (2+4) + (2+4+6) + (2+4+6+8) + ... + (2+4+6+8+...+2n) in C++
In this problem, we are given a number n which defines the nth term of the series 2 + (2+4) + (2+4+6) + (2+4+6+8) + ... + (2+4+6+8+...+2n). Our task is to create a program to find the sum of the series.Let’s take an example to understand the problem,Input n = 3OutputExplanation − sum = (2) + (2+4) + (2+4+6) = 2 + 6 + 12 = 20A simple solution to the problem is to use a nested loop. The inner loop finds the ith element of the series and then add up all elements to the sum variable.ExampleProgram to illustrate the working of our solution,#include using namespace std; int calcSeriesSum(int n) { int sum = 0; for (int i = 1; i
Read MoreSum of the series 2^0 + 2^1 + 2^2 +...+ 2^n in C++
In this problem, we are given a number n which defines the n-th term of the series 2^0, 2^1, 2^2, …, 2^n. Our task is to create a program to find the sum of the series 2^0 + 2^1 + 2^2 +...+ 2^n.Let’s take an example to understand the problem, Inputn=6Output Explanation sum = 2^0 + 2^1 + 2^2 + 2^3 + 2^4 + 2^5 + 2^6 sum = 1 + 2 + 4 + 8 + 16 + 32 + 64 = 127A simple solution to the problem is by using the loop. Finding the 2^i, for each value from 0 ...
Read MoreSum of upper triangle and lower triangle in C++
In this problem, we are given a matrix. Our task is to create a program to print the sum of upper triangle and lower triangle.Lower triangleM00 0 0 … 0 M10 M11 0 … 0 M20 M21 M22 … ...
Read MoreSum of XOR of all pairs in an array in C++
In this problem, we are given an array arr[] of n integers. Our task is to create a program to find the sum of XOR of all pairs in an array.Let’s take an example to understand the problem, Input: arr[] = {5, 1, 4} Output: 10 Explanation: the sum of all pairs: 5 ^ 1 = 4 1 ^ 4 = 5 5 ^ 4 = 1 sum = 4 + 5 + 1 = 10One simple approach to solve this problem is to run nested loops and find all pairs of numbers. Find XOR of each pair and add ...
Read MoreSum of XOR of all possible subsets in C++
In this problem, we are given an array aar[] of n numbers. Our task is to create a program to find the Sum of XOR of all possible subsets.Here, we will find all subsets of the array. Then for each subset, we will find the XOR of elements of the subset and add them to the sum variable.Let’s take an example to understand the problem, Input: arr[] = {5, 1, 4} Output: 20 Explanation: XOR of all subsets: {5} = 5 {1} = 1 {4} = 4 {5, 1} = 4 {5, 4} = 1 {1, 4} = 5 {5, ...
Read MoreSum of XOR of all subarrays in C++
In this problem, we are given an array arr[] of n numbers. Our task is to create a program to find the sum of XOR of all subarrays of the array.Here, we need to find all sub-arrays of the given array, and then for each subarray, we will find the xor of element and add the XOR value to the sum variable.Let’s take an example to understand the problem, Input: arr[] = {5, 1, 4} Output: Explanation: XOR of all subarrays for the array : XOR {5} = 5 XOR {1} = 1 XOR {4} = 4 XOR {5, 1} ...
Read MoreSum of the series Kn + ( K(n-1) * (K-1)1 ) + ( K(n-2) * (K-1)2 ) + ... (K-1)n in C++
In the problem, we are ginen two number k and n of the series K^n + ( K^(n-1) * (K-1)^1 ) + ( K^(n-2) * (K-1)^2 ) + ... (K-1)^n. Our task is to create a program to find the sum of the series.Let’s take an example to understand the problem, Input: n = 3, k = 4 Output: 175 Explanation: Sum of the series is = 4^3 + ( (4^2)*(3^1) ) + ( (4^1)*(3^2) ) + ( (4^0)*(3^3) ) = 64 + 48 + 36 + 27 = 175A simple way to solve the problem, is using a for ...
Read MoreSum of two numbers where one number is represented as array of digits in C++
In this problem, we are given two numbers, from which one is represented using array of digits. Our task is to create a program that will find the sum of two numbers where one number is represented as array of digits.Let’s take an example to understand the problem, Input: n = 213, m[] = {1, 5, 8, } Output: 371 Explanation: 213 + 158 = 371To solve this problem, we will simply digit by digit from the number which element of the array. It lsb of the number is added to the (n-1)th element of the array. The carry will ...
Read MoreBinary Indexed Tree: Range Update and Range Queries in C++
Here, we are given an array of size n which initially has all elements 0. And there are some queries that are to be performed on it. There are two types of queries −update(l, r, value) − Add value to the elements of the array that are between index l to r. For example, update(2, 4, 5) will update the array by placing the element 2 at the element at index 4 and 5.getRangeSum(l, r) − Find the sum of elements within the range of elements from l to r. For example, getRangeSum(4, 7) will find the sum of all ...
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