To query an array of embedded documents based on range, use aggregate(). Let us create a collection with documents −> db.demo346.insertOne( ...    { ...       _id: 101, ...       userDetails: [ ...          { UserName: "Chris", Score:78}, ...         ... Read More

Let us create a collection with documents −> db.demo345.insertOne({ ...    "UserName" : "Robert", ...       "UserDetails" : [ ...          { ...             "isMarried" : false, ...             "CountryName":"US" ... ...       ... Read More

Let us create a collection with documents −> db.demo344.insertOne({"startDate":"2020-02-24 10:50:00", "endDate":"2020-02-24 11:50:00"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e53f52cf8647eb59e5620aa") } > db.demo344.insertOne({"startDate":"2020-02-24 08:00:00", "endDate":"2020-02-24 11:50:50"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e53f53df8647eb59e5620ab") }Display all documents from a collection with the help of find() method −> db.demo344.find();This ... Read More

For such conversion, use aggregate. Let us create a collection with documents −> db.demo343.insertOne({ ...    _id: 101, ...    UserName: "Chris", ...    details: [ ...       {"Name":"John"}, ...       {"Name":"David"} ...    ] ... } ... ); { "acknowledged" : true, "insertedId" : 101 ... Read More

To get only specific fields in nested array documents, use $filter along with $project. Let us create a collection with documents −> db.demo342.insertOne({ ...    "Id": "101", ...       "details1" : { ...          "details2" : [ ...             { ... Read More

To find value in an array within a range, use $gt and $lt. Let us create a collection with documents −> db.demo341.insertOne({ ...    "Name": "Chris", ...       "productDetails" : [ ...          { ...             "ProductPrice" : { ... ... Read More

To get only a single result, use findOne() and fetch on the basis of id. Let us create a collection with documents −> db.demo340.insertOne({_id:1, "Name":"Chris", Age:21}); { "acknowledged" : true, "insertedId" : 1 } > db.demo340.insertOne({_id:2, "Name":"David", Age:23}); { "acknowledged" : true, "insertedId" : 2 } > db.demo340.insertOne({_id:3, "Name":"Bob", Age:20}); ... Read More

For this, use aggregate along with $zip. The zip is used to transpose an array. Let us create a collection with documents −> db.demo339.insertOne({Id:101, Score1:["98", "56"], Score2:[67, 89]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e529ee5f8647eb59e5620a2") }Display all documents from a collection with the help of find() method −> ... Read More

The $concatArrays is used to concatenate arrays to return the concatenated array.Let us create a collection with documents −> db.demo338.insertOne({"Name":"Chris", "Marks1":[ [56, 67, 45], [67, 89, 90, 91]]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5299baf8647eb59e56209f") }Display all documents from a collection with the help of find() method −> ... Read More

To get the sum, use $sum along with aggregate(). Let us create a collection with documents −> db.demo337.insertOne({"Amount":100}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5231e5f8647eb59e56209b") } > db.demo337.insertOne({"Amount":500}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5231e9f8647eb59e56209c") } > db.demo337.insertOne({"Amount":400}); {    "acknowledged" : true,    "insertedId" : ... Read More