To find when the keys are unknown, use $addField and $objectToArray. Let us first create a collection with documents −> db.demo375.insertOne( ...    { ...       "details":{ ...          "Name":"John", ...          "Age":23 ...       } ...    } ... ... Read More

To group by another field, use $group along with $project. Let us first create a collection with documents −> db.demo374.insertOne( ...    { ... ...       "Name" : "Chris", ...       "HobbyDetails" : [ ...          "Reading Book", ...         ... Read More

Let us first create a collection with documents −> db.demo373.createIndex({"Name":1, "CountryName":1}); {    "createdCollectionAutomatically" : true,    "numIndexesBefore" : 1,    "numIndexesAfter" : 2,    "ok" : 1 } > db.demo373.insertOne({"Name":"Chris", "Age":22, "CountryName":"US"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e59ffde2ae06a1609a00aff") } > db.demo373.insertOne({"Name":"David", "Age":21, "CountryName":"AUS"}); {    "acknowledged" ... Read More

The $ifNull evaluates an expression and returns the value of the expression if the expression evaluates to a non-null value.Let us first create a collection with documents −> db.demo372.insertOne({"FirstName":"Chris"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e591aea2ae06a1609a00af6") } > db.demo372.insertOne({"FirstName":null}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e591aef2ae06a1609a00af7") ... Read More

To change the primary key, you need to first delete it. Use forEach() along with delete to remove and then get a new primary key. Let us create a collection with documents −> db.demo41.insertOne({"StudentName":"Carol"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e25ce4acfb11e5c34d898e3") }Display all documents from a collection with ... Read More

Let us first create a collection with documents −> db.demo371.insertOne({"Name":"David", "CountryName":"US"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e57f6982ae06a1609a00af2") } > db.demo371.insertOne({"Name":"John", "CountryName":"UK"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e57f69e2ae06a1609a00af3") } > db.demo371.insertOne({"Name":"Bob", "CountryName":"AUS"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e57f6a42ae06a1609a00af4") } > db.demo371.insertOne({"Name":"Mike", "CountryName":"US"}); ... Read More

For this, use save() in MongoDB. Following is the syntax −var anyVaribaleName=yourValue db.anyCollectionName.save(yourVariableName); yourVariableName;Let us first create an object for our example −> var studentDetails={"StudentName":"Chris", "ListOfMarks":[56, 78, 89], "ListOfSubject":["MySQL", "Java", "MongoDB"]};Let us save the above created object “studentDetails” −> db.demo40.save(studentDetails); WriteResult({ "nInserted" : 1 })Let us display the value −> ... Read More

For this, use $all in MongoDB. The $all operator in MongoDB selects the documents where the value of a field is an array that contains all the specified elements.Let us first create a collection with documents −> db.demo370.insertOne( ...    { ...       "Name" : "Chris", ...   ... Read More

At first, switch to a particular database in MongoDB with the USE command as in the below syntax −use yourDatabaseName; db.getCollectionNames();Let us implement the above syntax to display collections of database WEB −> use web; switched to db web > db.getCollectionNames();This will produce the following output −[ ... Read More

Yes, it is possible using the UPDATE() method. Let us create a collection with documents −> db.demo27.insertOne({"StudentDetails":{"101":{"Subject":["Java"]}}}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e15f9e822d07d3b95082e7f") } > db.demo27.insertOne({"StudentDetails":{"101":{"Subject":["MySQL"]}}}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e15f9eb22d07d3b95082e80") }Display all documents from a collection with the help of find() method ... Read More