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AmitDiwan has Published 10744 Articles

AmitDiwan
264 Views
To filter out sub documents, use MongoDB aggregate and in that, use $unwind. Let us create a collection with documents −> db.demo662.insertOne( ... { ... "details":[ ... { ... Name:"Chris", ... Marks:35 ... }, ... { ... ... Read More

AmitDiwan
443 Views
For faster search, create index. For this, use createIndex(). Let us create a collection with documents −> db.demo661.createIndex({ListOfName:1}); { "createdCollectionAutomatically" : true, "numIndexesBefore" : 1, "numIndexesAfter" : 2, "ok" : 1 } > db.demo661.insertOne({_id:1, ListOfName:["John", "Robert", "David"]}); { "acknowledged" : true, "insertedId" : 1 } > ... Read More

AmitDiwan
398 Views
You can use $group. Let us create a collection with documents −> db.demo659.insertOne({Name:"Chris", CountryName:"US", "Marks":50}); { "acknowledged" : true, "insertedId" : ObjectId("5ea1a50724113ea5458c7cf9") } > db.demo659.insertOne({Name:"David", CountryName:"US", "Marks":60}); { "acknowledged" : true, "insertedId" : ObjectId("5ea1a50724113ea5458c7cfa") } > db.demo659.insertOne({Name:"Mike", CountryName:"US", "Marks":55}); { "acknowledged" : true, "insertedId" ... Read More

AmitDiwan
209 Views
For unique index, set unique − true while creating an index. Let us create a collection with documents −> db.demo658.createIndex({FirstName:1}, {unique:true, sparse:true}); { "createdCollectionAutomatically" : true, "numIndexesBefore" : 1, "numIndexesAfter" : 2, "ok" : 1 } > > db.demo658.insertOne({"FirstName":"John", "LastName":"Smith"}); { "acknowledged" : true, ... Read More

AmitDiwan
173 Views
To group by dates, use $group in MongoDB aggregate. Let us create a collection with documents −> db.demo657.insertOne({ ... id: 1, ... Name: "Chris", ... DueDate: new ISODate("2020-04-22") ... } ... ); { "acknowledged" : true, "insertedId" : ... Read More

AmitDiwan
240 Views
To push and slice in MongoDB, use $push and $slice. Let us create a collection with documents −> db.demo656.insertOne({Name:"John"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea060264deddd72997713cf") }Display all documents from a collection with the help of find() method −> db.demo656.find();This will produce the following output −{ "_id" : ... Read More

AmitDiwan
2K+ Views
To clear, use dropDatabase. Following is the syntax −use yourDatabaseName; db.dropDatabase();To clear a MongoDB database, first show all the databases −> show dbsThis will produce the following output −MyDB 0.000GB admin 0.000GB config 0.000GB local 0.000GB onlinecustomertracker 0.000GB test 0.006GBNow, let us delete the database ... Read More

AmitDiwan
648 Views
The findOne() returns one document that satisfies the specified query criteria on the collection. Let us create a collection with documents −> db.demo655.insertOne({subject:"MySQL"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea050254deddd72997713cc") } > db.demo655.insertOne({subject:"MongoDB"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea0502b4deddd72997713cd") } > db.demo655.insertOne({subject:"Java"}); { "acknowledged" ... Read More

AmitDiwan
101 Views
Yes, using $in is faster. Let us see an example and create a collection with documents −> db.demo653.insertOne({subject:"MySQL"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea04b274deddd72997713c0") } > db.demo653.insertOne({subject:"MongoDB"}); { "acknowledged" : true, "insertedId" : ObjectId("5ea04b304deddd72997713c1") } > db.demo653.insertOne({subject:"Java"}); { "acknowledged" : true, "insertedId" : ... Read More

AmitDiwan
214 Views
Use $sort in MongoDB aggregation. Let us create a collection with documents −> db.demo652.insertOne({ ... value:10, ... "details" : [{ ... "ProductName" : "Product-1", ... "ProductQuantity" : 8, ... "ProductPrice" : 500 ... }, { ... ... Read More