Server Side Programming Articles - Page 1831 of 2650

Suppose we have to create an iterator that iterates through a run-length encoded sequence. Here the iterator is initialized by calling RLEIterator(int[] A), where A is a run-length encoding of a sequence. So we can say that for all even i, A[i] tells us the number of times that the non-negative integer value A[i+1] is repeated in the sequence. Here iterator supports one function −next(int n): This function exhausts the next n elements (n >= 1) and returns the last element exhausted in this way. So if there is no element left to exhaust, next returns -1 instead.Suppose we start ... Read More

Suppose we have an array A of non-negative integers. For every (contiguous) subarray say B = [A[i], A[i+1], ..., A[j]] (with i

Suppose we have a set of N people (they are numbered 1, 2, ..., N), we would like to split everyone into two subgroups of any size. Now each person may dislike some other people, and they should not go into the same group. So, if dislikes[i] = [a, b], it indicates that it is not allowed to put the people numbered a and b into the same group. We have to find if it is possible to split everyone into two groups in this way.So if the input is like N = 4 and dislike = [[1, 2], [1, ... Read More

Suppose we have a 2 dimensional grid with R rows and C columns, we start from (r0, c0) facing east. Here, the north-west corner of the grid is at the first row and column, and the south-east corner of the grid is at the last row and column. We will walk in a clockwise spiral shape to visit every position in this grid. When we are at the outside the boundary of the grid, we continue our walk outside the grid (but may return to the grid boundary later.). We have to find a list of coordinates representing the positions ... Read More

Suppose we have an array called people. Now the i-th person has weight people[i], and each boat can carry a maximum weight of limit. If each boat carries at most 2 people at the same time, provided the sum of the weight of those people is at most limit. We have to find the minimum number of boats to carry every given person. So if the input is like [3,2,1,2], and limit is 3, then we need three boats. [(1,2), (2), (3)].To solve this, we will follow these steps −sort the people arrayi := 0, j := size of people array – 1, ret := 0while i

Suppose we have two players Alex and Lee they play a game with piles of stones. There are an even number of piles that are arranged in a row, and each pile has some number of stones piles[i]. The objective of the game is to end with the most stones. When the total number of stones is odd, there are no ties. Alex and Lee take turns, with Alex starting first. In each turn, a player takes the entire pile of stones from either the beginning or the end of the row. This will be continued until there are no ... Read More

Suppose we have N piles of bananas, the i-th pile has piles[i] bananas. Here the guards have gone and will come back in H hours. Koko can decide her bananas-per-hour eating speed is K. Each hour, she takes some pile of bananas, and eats K bananas from that pile. If the pile has less than K bananas, then she consumes all of them instead, and won't eat any more bananas during this hour. Consider Koko likes to eat slowly, but still wants to finish eating all the bananas before the guards come back. We have to find the minimum integer ... Read More

Suppose we have a sequence X_1, X_2, ..., X_n is fibonacci-like if −n >= 3X_i + X_{i+1} = X_{i+2} for all i + 2 = 3 otherwise return 0.Let us see the following implementation to get better understanding −Example Live Demo#include using namespace std; class Solution {    public:    int lenLongestFibSubseq(vector & A) {       int ret = 0;       unordered_map m;       int n = A.size();       vector < vector > dp(n, vector (n));       for(int i = 0; i < n; i++){       ... Read More

Suppose we have a positive integer N, we reorder the digits in any order (including the original order) such that the leading digit is non-zero. We have to check whether we can do this in a way such that the resulting number is a power of 2. So if the number is like 46, then the answer will be true.To solve this, we will follow these steps −Define a method called count, this will take x as inputret := 0while x is not 0ret := ret + 10 ^ last digit of xx := x / 10return retFrom the main ... Read More

Suppose we have to find the smallest prime palindrome that is greater than or equal to N. So if the N is 13, then the smallest palindrome will be 101.To solve this, we will follow these steps −If N is in range 8 to 11, then return 11for i in range 1 to 99999s := i as a stringr := sreverse rnum := concatenate s and substring of r from index 1, then convert to numberif num >= N and num is prime, then return numreturn 0Let us see the following implementation to get better understanding −Example Live Demo#include using ... Read More