In this article, we will learn to calculate the product of the unique prime factors of a given number using Java. Prime factorization plays a crucial role in many mathematical and computational problems, and understanding how to work with prime factors can help you solve complex challenges efficiently.  Problem Statement Given a positive integer n, the task is to find the product of the unique prime factors of n. The objective is to calculate the product of all distinct prime factors of n that divide it exactly. Input  68 Output  34 Since the unique prime factors of 68 are 2 ... Read More

In mathematics, the factors of a number are the integers that divide the number without leaving a remainder. For a given number, finding the minimum sum of its factors involves identifying a pair of factors whose sum is the smallest among all possible factor pairs. In this article, we will learn to find the minimum sum of factors of a number we will be using the Integer class and Math class in Java − Integer class The Java Integer class serves as a wrapper for the primitive int type, encapsulating a single integer value within an object. For Integer.MAX_VALUE, which provides ... Read More

To expand a String if range is given, the Java code is as follows −Example Live Demopublic class Demo {    public static void expand_range(String word) {       StringBuilder my_sb = new StringBuilder();       String[] str_arr = word.split(", ");       for (int i = 0; i < str_arr.length; i++){          String[] split_str = str_arr[i].split("-");          if (split_str.length == 2){             int low = Integer.parseInt(split_str[0]);             int high = Integer.parseInt(split_str[split_str.length - 1]);             while (low

To count trailing zeroes in factorial of a number, the Java code is as follows −Example Live Demoimport java.io.*; public class Demo{    static int trailing_zero(int num){       int count = 0;       for (int i = 5; num / i >= 1; i *= 5){          count += num / i;       }       return count;    }    public static void main (String[] args){       int num = 1000000;       System.out.println("The number of trailing zeroes in " + num +" factorial is " + ... Read More

To count the occurrence of each character in a string using Hashmap, the Java code is as follows −Example Live Demoimport java.io.*; import java.util.*; public class Demo{    static void count_characters(String input_str){       HashMap my_map = new HashMap();       char[] str_array = input_str.toCharArray();       for (char c : str_array){          if (my_map.containsKey(c)){             my_map.put(c, my_map.get(c) + 1);          }else{             my_map.put(c, 1);          }       }       for (Map.Entry entry : my_map.entrySet()){ ... Read More

To count the characters in each word in a given sentence, the Java code is as follows −Example Live Demoimport java.util.*; public class Demo{    static final int max_chars = 256;    static void char_occurence(String my_str){       int count[] = new int[max_chars];       int str_len = my_str.length();       for (int i = 0; i < str_len; i++)       count[my_str.charAt(i)]++;       char ch[] = new char[my_str.length()];       for (int i = 0; i < str_len; i++){          ch[i] = my_str.charAt(i);          int find = 0;          for (int j = 0; j

To convert Iterator to Spliterator, the Java code is as follows −Example Live Demoimport java.util.*; public class Demo{    public static Spliterator getspiliter(Iterator iterator){       return Spliterators.spliteratorUnknownSize(iterator, 0);    }    public static void main(String[] args){       Iterator my_iter = Arrays.asList(56, 78, 99, 32, 100, 234).iterator();       Spliterator my_spliter = getspiliter(my_iter);       System.out.println("The values in the spliterator are : ");       my_spliter.forEachRemaining(System.out::println);    } }OutputThe values in the spliterator are : 56 78 99 32 100 234A class named Demo contains a function named ‘getspiliter’ that returns a spliterator. In ... Read More

To check whether it is possible to make a divisible by 3 number using all digits in an array, the Java code is as follows −Example Live Demoimport java.io.*; import java.util.*; public class Demo{    public static boolean division_possible(int my_arr[], int n_val){       int rem = 0;       for (int i = 0; i < n_val; i++)       rem = (rem + my_arr[i]) % 3;       return (rem == 0);    }    public static void main(String[] args){       int my_arr[] = { 66, 90, 87, 33, 123}; ... Read More

To check if the count of divisors is even or odd, the Java code is as follows −Example Live Demoimport java.io.*; import java.math.*; public class Demo{    static void divisor_count(int n_val){       int root_val = (int)(Math.sqrt(n_val));       if (root_val * root_val == n_val){          System.out.println("The number of divisors is an odd number");       }else{          System.out.println("The number of divisors is an even number");       }    }    public static void main(String args[]) throws IOException{       divisor_count(25);    } }OutputThe number of divisors is an ... Read More

The given article involves determining if all digits of a positive integer can divide the number without leaving a remainder. If any digit is zero or does not divide the number the result is false; otherwise, it is true using Java. This can be solved using two approaches: the Naive-Based Approach, which relies on arithmetic operations, and the String-Based Approach, which uses string manipulation for digit processing. Both methods ensure each digit meets the divisibility condition efficiently. Approaches to Check If All Digits of a Number Divide It Following are the different approaches to check if all digits of a ... Read More