A neon number is a number where the sum of digits of the square of the number is equal to the number. Let's take an example.n = 9square = 81sum of digits of square = 8 + 1 = 9So, the number 9 is a neon number.We need to check whether the given number is a neon number or not. If the given number is a neon number, then print Yes else print No.AlgorithmInitialise the number n.Find the square of the number.Find the sum of the digits of the squareIf the sum of digits of the square is equal to ... Read More

We are given a number n, we need to find the nearest prime number that is less than n. We can find the number easily if we start checking from the n - 1. Let's see some examples.Input10Output7AlgorithmInitialise the number n.Write a loop that iterates from n - 1 to 1Return the first prime number that you foundReturn -1 if you didn't find any prime that's less than given nImplementationFollowing is the implementation of the above algorithm in C++#include using namespace std; bool isPrime(int n) {    if (n == 2) {       return true;    } ... Read More

In this article, we will show you how to find the minimum distance from each cell in a binary matrix to the nearest cell that contains the digit 1. We will see brute force as well as optimized approaches. Problem Statement Given a binary matrix, our task is to calculate the minimum distance for each cell to the nearest cell that contains the value 1, and if the current cell itself has 1 as a value, the distance will be 0. If the input matrix is as follows - 0 0 1 1 1 0 0 0 0 The ... Read More

In this article, we will cover C++ programs to work with natural numbers. we use natural numbers in various operations, such as indexing arrays, performing loops, and validating user input. we will also write code to demonstrate how natural numbers can be used for these purposes in C++. Natural Numbers are a set of positive numbers, starting from 1 and going to infinity. natural numbers are: 1, 2, 3, 4, 5... etc In C++, understand concepts like conditions, loops, and how we store and manipulate variables. We will provide everything you need to know about natural numbers along with programs. ... Read More

A smart number is a number that contains at least three distinct prime factors. You are given a number N. Find the n-th smart number.The smart number series are30, 42, 60, 66, 70, 78...AlgorithmInitialise the number N.Initialise the count to 0.Write a function that checks whether the given number is prime or not.Write a function that checks whether the number is smart or not.Write a loop that iterates from 30 as first smart number is 30.Check whether the current number is smart number or not using the prime number function.Increment the count by 1 when you find a smart number.Return ... Read More

In this tutorial, we are going to write a program that finds the n-th pentagonal number.A pentagonal number is a number represented as dots or pebbles arranged in the shape of a regular polygon. Refer to the wiki for better understanding.The n-th pentagonal number is (3 * n * n - n) / 2.The series of pentagonal numbers are 1, 5, 12, 22, 35, 51, 70, 92...AlgorithmInitialise the number n.Use the formula to find the n'th pentagonal number.Print the resultant number.ImplementationFollowing is the implementation of the above algorithm in C++#include using namespace std; int getNthPentagonalNumber(int n) {   ... Read More

To find the n-th palindrome of k digits, we can iterate from the first k digits number till we find the n-th palindrome number. This approach is not efficient. You can try it yourself.Now, let's see the efficient approach to find the n-th palindrome of k digits.There are two halves in the numbers. The first half is equal to the reverse of the second half.The first half of the n-th number with k digits areIf k is odd then (n - 1) + 10k/2else(n-1)+10k/2-1The second half of the n-th number with k digits will be the reverse of the first ... Read More

The given series is 1, 17, 98, 354...If you clearly observe the series, you will find that the n-th number is equal to the 4 powers.Let's see the pattern. 1 = 1 ^ 4 17 = 1 ^ 4 + 2 ^ 4 98 = 1 ^ 4 + 2 ^ 4 + 3 ^ 4 354 = 1 ^ 4 + 2 ^ 4 + 3 ^ 4 + 4 ^ 4 ...AlgorithmInitialise the number N.Initialise the result to 0.Write a loop that iterates from 1 to n.Add 4th power current number to the result.Print the result.ImplementationFollowing is the implementation of the above algorithm in C++#include using namespace std; int getNthTerm(int n) {    int nthTerm = 0;    for (int i = 1; i

The given series is 1, 11, 55, 239, 991...If you clearly observe the series, you will find that the n-th number is 4n-2n-1.AlgorithmInitialise the number N.Use the series formula to compute the n-th term.Print the result.ImplementationFollowing is the implementation of the above algorithm in C++#include using namespace std; int getNthTerm(int n) {    int num = pow(4, n) - pow(2, n) - 1;    return num; } int main() {    int n = 7;    cout

The given series is 2, 12, 36, 80, 150...If you clearly observe the series, you will find that the n-th number is n2 + n3.AlgorithmInitialise the number N.Use the series formula to compute the n-th term.Print the result.ImplementationFollowing is the implementation of the above algorithm in C++#include using namespace std; int getNthTerm(int n) {    return (n * n) + (n * n * n); } int main() {    int n = 7;    cout