Programming Articles - Page 2472 of 3366

A yield() method is a static method of Thread class and it can stop the currently executing thread and will give a chance to other waiting threads of the same priority. If in case there are no waiting threads or if all the waiting threads have low priority then the same thread will continue its execution. The advantage of yield() method is to get a chance to execute other waiting threads so if our current thread takes more time to execute and allocate processor to other threads. Syntax public static void yield() Example class MyThread extends Thread { public void run() { ... Read More

Here we will see the area of largest rectangle that can be inscribed in an ellipse. The rectangle in ellipse will be like below −The a and b are the half of major and minor axis of the ellipse. The upper right corner of the rectangle is (x, y). So the area isNow, after making this equation as f(x) and maximizing the area, we will get the area asExample#include #include using namespace std; float area(float a, float b) {    if (a < 0 || b < 0 ) //if the valuse are negative it is invalid   ... Read More

Here we will see how to get the area of the circle which is inscribed in N-sided regular polygon. The N (number of sides) are given, and each side of the polygon is ‘a’The approach is simple. One N sided polygon can be divided into N equal triangles, the whole angle for each triangle in center is 360/N, so −Example#include #include using namespace std; float area(float n, float a) {    if (n < 0 || a < 0 ) //if the valuse are negative it is invalid       return -1;    float r = a/(2.0*tan((180/n) ... Read More

Here we will see how to get the area of one hexagon using diagonal length. The diagonal length of the hexagon is d.The interior angles of a regular hexagon are 120° each. The sum of all interior angles are 720°. If the diagonal is d, then area is −Example#include #include using namespace std; float area(float d) {    if (d < 0) //if d is negative it is invalid       return -1;    float area = (3 * sqrt(3) * d*d)/8.0;    return area; } int main() {    float r = 10;    cout

Here we will see how to get the area of decagon which is present inside the circle. The radius is given. The side of the decagon is ‘a’.As we know that the side of the decagon is like below −So the area is −Example#include #include using namespace std; float area(float r) {    if (r < 0) //if r is negative it is invalid       return -1;    float area = (5 * pow(r, 2) * (3 - sqrt(5)) * (sqrt(5) + (2 * sqrt(5)))) / 4;    return area; } int main() {    float r = 8;    cout

Here we will see how to get the area of circumcircle of a right angled triangle. The hypotenuse of the triangle is forming the diameter of the circle. So if the hypotenuse is h, then radius is h/2So the area is −Example Code#include #include using namespace std; float area(float h) {    if (h < 0) //if h is negative it is invalid       return -1;    float area = 3.1415 * (h/2) * (h/2);    return area; } int main() {    float h = 8;    cout

Here we will see the area of circle which is inscribed in an equilateral triangle. The sides of the triangle are ‘a’.The area of equilateral triangle −The semi-perimeter of the triangle is −So the radius of the circle is −Example#include #include using namespace std; float area(float a) {    if (a < 0 ) //if the value is negative it is invalid       return -1;    float area = 3.1415 * (a/(2*sqrt(3))) * (a/(2*sqrt(3)));    return area; } int main() {    float a = 4;    cout

Here we will see the area of circle which is inscribed in a rhombus. The diagonals of the rhombus are ‘a’ and ‘b’. The radius of the circle is h.Two diagonals are creating four equal triangles. Each triangle is right-angled triangle, so their area is −Each side of the rhombus is the hypotenuses −So the area of the circle is −Example#include #include using namespace std; float area(float a, float b) {    if (a < 0 || b < 0) //if the values are negative it is invalid       return -1;    float area = (3.1415 ... Read More

Here we will see the area of a triangle which in inscribed in one rectangle and that circle is inscribed in an ellipse. The half of the major and minor axis are ‘a’ and ‘b’ respectively. Suppose the length of the rectangle is ‘l’ and breadth is ‘h’We know that the area of the rectangle in an ellipse is −The area of the triangle is −Example#include #include using namespace std; float area(float a, float b) {    if (a < 0 || b < 0) //if the values are negative it is invalid       return -1; ... Read More

Here we will see the area of a square which in inscribed in one circle and that circle is inscribed in a hexagon. The side of the square is ‘a’. The radius of the circle is ‘r’, and the side of the hexagon is ‘A’. The diagram will be like below.We know that the radius of a circle inscribed in a hexagon is −Also the radius of the circle is half of the diagonal of the square. So −Then we can say −Then the area will be −Example#include #include using namespace std; float area(float A) { //A is ... Read More