Programming Articles - Page 2054 of 3363

Suppose we have a string s, we have to find the maximum number of occurrences of any substring that satisfies the following rules −The number of distinct characters in the substring must be less than or equal to maxLetters.The substring size must be in range minSize and maxSize inclusive.So if the input is like − “aababcaab”, maxLetters = 2, minSize = 3 and maxSize = 4, then the output will be 2. The substring "aab" has 2 occurrences in the original string. This satisfies the conditions, 2 unique letters and size 3 (between minSize and maxSize).To solve this, we will ... Read More

Suppose we have a m x n matrix mat and an integer threshold. We have to the maximum side-length of a square with a sum less than or equal to the given threshold or return 0 if there is no such square. So if the input is like −113243211324321132432113243211324321132432And threshold is 4, then output will be 2, as there are two squares of side length 2, so max is 2To solve this, we will follow these steps −Define a method called ok, this will take x and matrix m and threshold thset curr := 0for i in range x – ... Read More

Suppose we have a list of intervals, we have to remove all intervals that are covered by another interval in the list. Here Interval [a,b) is covered by interval [c,d) if and only if c

Suppose we have to design an Iterator class, that consists of few operations −Define a constructor that takes a string characters of sorted distinct lowercase English letters and a number combinationLength as parameter.Define a function next() that returns the next combination of length combinationLength in alphabetic order.Define another function hasNext() that returns True if and only if there exists a next combination.So if the input is like −CombinationIterator iterator = new CombinationIterator("xyz", 2); iterator.next(); // returns "xy" iterator.hasNext(); // returns true iterator.next(); // returns "xz" iterator.hasNext(); // returns true iterator.next(); // returns "yz" iterator.hasNext(); // returns falseTo solve this, we ... Read More

Suppose we have a tree, this tree is rooted at node 0, this is given as follows −Number of nodes is nodesValue of ith node is value[i]Parent of ith node is parent[i]We have to remove every subtree whose sum of values of nodes is 0, after doing that return the number of nodes remaining in the tree. So if the tree is like −There are 7 nodes, the output will be 2To solve this, we will follow these steps −Create a map called childrendefine a method called dfs(), this will take node, an array value and graphtemp := a pair ... Read More

Suppose we have a sorted list of disjoint intervals, each interval intervals[i] = [a, b] represents the set of numbers x such that a b[0], then swap a and bif a and b are intersecting, then call manipulate2(ans, t)return ansExample(C++)Let us see the following implementation to get a better understanding − Live Demo#include using namespace std; void print_vector(vector v){    cout

Suppose we have an array of integers nums and an integer k. A subarray is known as nice subarray if there are k odd numbers on it. We have to find the number of nice sub-arrays. So if the array is [1, 1, 2, 1, 1], and k = 3, then the output will be 2, as the subarrays are [1, 1, 2, 1], and [1, 2, 1, 1]To solve this, we will follow these steps −ans := 0, n := size of nums arrayleft := 0 and right := 0, and count := 0define an array odd, fill this ... Read More

Suppose we have two strings s1 and s2 of equal length consisting of letters only "x" and "y". Our task is to make these two strings equal to each other. We can swap any two characters that belong to different strings, which means − swap s1[i] and s2[j]. We have to find the minimum number of swaps required to make s1 and s2 equal, or return -1 if it is impossible to do so. So if the strings are s1 = “xy” and s2 = “yx”, then the output will be 2. If we swap s1[0] and s2[0], s1 = ... Read More

Suppose we have an undirected tree; we have to find its diameter − the number of edges in the longest path in that tree is the diameter of that tree. Here tree is given as an edge list where edges[i] = [u, v] is a bidirectional edge between nodes u and v. Each node has labels in the set {0, 1, ..., edges.length}. So if the graph is like −The output will be 4.To solve this, we will follow these steps −Define a map ldefine a method called dfs(). this will take v, an array called visited, the graph and ... Read More

Suppose we have to design a Leaderboard class, there are three different functions −addScore(playerId, score) − This will update the leaderboard by adding score to the given player's score. When there is no such player with given id in the leaderboard, add him to the leaderboard with the given score.top(K) − This will return the score sum of the top K players.reset(playerId) − This will reset the score of the player with the given id to 0. It is guaranteed that the player was added to the leaderboard before calling this function.Initially, the leaderboard should empty.If we perform the operations ... Read More