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Programming Articles - Page 1580 of 3363
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We are given a string str. The goal is to count the number of substrings in str that have each character occurring utmost k times. For example if input is “abc” and k=1, the substrings will be “a”, “b”, “c”, “ab”, “bc”, “abc”.Let us understand with examples.Input − str=”abaefgf”Output − Count of substrings with same first and last characters are &mmius; 9Explanation − Substrings will be“a”, “b”, “a”, “e” ,”f”, “g”, “f”, “aba”, “fgf”. Total 9.Input − str=”abcdef”Output − Count of substrings with same first and last characters are: 6Explanation − Substrings will be -“a” , “b” , “c”, “d”, ... Read More
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We are given a string str. The goal is to count the number of substrings in str that have the same starting and ending character. For example, if input is “baca” substrings will be “b”, “a”, “c”, “a”, “aca”. Total 5.Let us understand with examples.Input − str=”abaefgf”Output −Count of substrings with same first and last characters are: 9Explanation − Substrings will be“a”, “b”, “a”, “e” ,”f”, “g”, “f”, “aba”, “fgf”. Total 9.Input − str=”abcdef”Output −Count of substrings with same first and last characters are: 6Explanation − Substrings will be −“a” , “b” , “c”, “d”, “e” ,”f”. Total 6The approach ... Read More
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We are given string str containing 0’s, 1’s, and 2’s only. The goal is to find all substrings of str that have equal numbers of 0’s 1’s and 2’s. If str is “12012”. Substrings with equal 0’s, 1’s, and 2’s will be “120”, “201” and “012”. The count will be 3.Let us understand with examples.Input − str=”112200120”Output −Count of Substrings with an equal number of 0s, 1s, and 2s are − 5Explanation − Substrings will bestr[0-5]=”112200”, str[1-6]=”122001”, str[5-7]=”012”, str[6-8]=”120”, str[7-0]=”201”Input − str=”12012”Output −Count of Substrings with an equal number of 0s, 1s, and 2s are: 3Explanation − Substrings will be ... Read More
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We are given with two strings str_1 and str_2 as input. The goal is to find the count of strings same as str_2 that can be constructed using letters picked from str_1 from which each character is used just once.Note − All alphabets in both are in the same case.Let us understand with examples.Input − str_1 = "abcaaaabca", str_2 = "bca";Output − Count occurrences of a string that can be constructed from another given string are: 2Explanation − Substrings bca in str_a −str_1[1-3]=”bca” and str[7-9]=”bca”Input − str_1 = "about", str_2 = "cout";Output − Count occurrences of a string that can ... Read More
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We are given a number N as input. The goal is to find all N digit numbers that have an odd number of 0’s as digits. The number also could have preceding zeros like in case of N=3 numbers included will be 000, 011, 012….990.Let us understand with examples.Input − N=3Output − Count of no. with N digits which consists of even number of 0's are − 244Explanation − All 3 digit numbers would be like −Smallest will be 000, then 011, 012, 013, 0014…..Highest will be 990.Input − N=5Output − Count of no. with N digits which consists of ... Read More
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We are given a number N as input. The goal is to find all N digit numbers that have an even number of 0’s as digits. The number also could have preceding zeros like in case of N=3 numbers included will be 001, 002, 003….010….so on.Let us understand with examples.Input − N=4Output − Count of no. with N digits which consists of even number of 0's are − 7047Explanation − All 4 digits numbers would be like −Smallest will be 0000, then 0011, 0012, 0013, 0014…..Highest will be 9900.Input − N=5Output − Count of no. with N digits which consists ... Read More
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Suppose we have a string s and another value k, We have to find a new string by taking each character from s and starting diagonally from top left to bottom right until reaching the kth line, then go up to top right, and so on.So, if the input is like s = "ilovepythonprogramming" k = 5, then the output will beTo solve this, we will follow these steps:line := a new mapcnt := 0delta := 1for each index i and character c in s, doinsert (c, i) at the end of line[cnt]cnt := cnt + deltaif cnt is same ... Read More
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Suppose we have a binary tree, we have to find the longest path that alternates between left and right child and going down.So, if the input is likethen the output will be 5 as the alternating path is [2, 4, 5, 7, 8].To solve this, we will follow these steps:if root is null, thenreturn 0Define a function dfs() . This will take node, count, flagif node is not null, thenif flag is same as True, thena := dfs(left of node, count + 1, False)b := dfs(right of node, 1, True)otherwise when flag is same as False, thena := dfs(right of ... Read More
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Suppose we have a list of words and a string called letters, we have to find the size of the longest word that can be made by rearranging the given letters. In the letters there may be asterisk character (*) it can match any character. And it is not necessary to use all the letters.So, if the input is like words = ["prince", "rice", "price", "limit", "hello"] letters = "*r**ce*", then the output will be 6, as the longest word we can make is "prince" the length is 6.To solve this, we will follow these steps:has := a map containing ... Read More