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Found 7442 Articles for Java

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To format a string, use the String.format() method in Java. The following is an example that formats a string %s.Example Live Demopublic class Demo { public static void main(String []args) { String str = String.format("%s %s", "demo", "text"); System.out.print("String: "+str); } }OutputString: demo textLeft pad a stringTo left pad a string, use the String.format and set the spaces.String.format("|%20s|", "demotext")If you add 30 above, it will display the first string after 30 spaces from the beginning.String.format("|%30s|", "demotext")The following is an example.Example Live Demopublic class Demo { public static void main(String []args) { ... Read More

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To left pad a string, use the String.format and set the spaces.String.format("|%20s|", "demotext")If you add 30 above, it will display the first string after 30 spaces from the beginning.String.format("|%30s|", "demotext")Example Live Demopublic class Demo { public static void main(String []args) { System.out.print(String.format("|%20s|", "demotext")); System.out.println("Left padded!"); } }Output| demotext|Left padded

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To right pad a string, use the String.format and set the spaces.String.format("%1$-" + 20 + "s", "demotext"));If you add 30 above, it will display the next string after 30 spaces from the beginning.String.format("%1$-" + 30 + "s", "demotext")The following is an example.Example Live Demopublic class Demo { public static void main(String []args){ System.out.print(String.format("%1$-" + 20 + "s", "demotext")); System.out.println("Right padded!"); } }Outputdemotext Right padded!

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The following are the conversion characters for date-time.CharacterDescriptioncComplete date and timeFISO 8601 dateDU.S. formatted date (month/day/year)T24-hour timer12-hour timeR24-hour time, no secondsYFour-digit year (with leading zeroes)yLast two digits of the year (with leading zeroes)CFirst two digits of the year (with leading zeroes)BFull month namebAbbreviated month namemTwo-digit month (with leading zeroes)dTwo-digit day (with leading zeroes)eTwo-digit day (without leading zeroes)AFull weekday nameaAbbreviated weekday namejThree-digit day of year (with leading zeroes)HTwo-digit hour (with leading zeroes), between 00 and 23kTwo-digit hour (without leading zeroes), between 0 and 23ITwo-digit hour (with leading zeroes), between 01 and 12lTwo-digit hour (without leading zeroes), between 1 and 12MTwo-digit minutes ... Read More

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In this article, we will learn how to format strings into a table using Java. Java's System.out.format() method is a convenient way to display formatted output. We will define a string format that specifies column widths to ensure uniform spacing, allowing us to create a neat table layout. By using this approach, we can display multiple rows of string data in a structured and readable format without manually adjusting spaces for each entry. Steps to format strings into a table Following are the steps to format strings into a table − Define a format string ... Read More

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Firstly, consider an object with date value.Object arrObj[] = { "Date", Calendar.getInstance() };After that, use the String.format() method to format Calendar and display the date.The following is an example.Example Live Demoimport java.util.Calendar; public class Demo { public static void main(String []args){ Object arrObj[] = { "Date", Calendar.getInstance() }; System.out.println("Formatting Date..."); System.out.println(String.format("%1$s = %2$tY %2$tm %2$te", arrObj)); } }OutputFormatting Date... Date = 2018 11 17

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To perform Bubble Sort, try the below given code. In this each each pair of adjacent elements is compared and the elements are swapped if they are not in order.The following is an example.Example Live Demopublic class Demo { public static void main(String []args) { String str[] = { "s", "k", "r", "v", "n"}; String temp; System.out.println("Sorted string..."); for (int j = 0; j < str.length; j++) { for (int i = j + 1; i < str.length; i++) { ... Read More

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To locate a substring in a string, use the indexOf() method.Let’s say the following is our string.String str = "testdemo";Find a substring ‘demo’ in a string and get the index.int index = str.indexOf( 'demo');Example Live Demopublic class Demo { public static void main(String []args) { String str = "testdemo"; System.out.println("String: "+str); int index = str.indexOf("demo"); System.out.printf("Substring 'demo' is at index %d", index); } }OutputString: testdemo Substring 'demo' is at index 4

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To locate a character in a string, use the indexOf() method.Let’s say the following is our string.String str = "testdemo";Find a character ‘d’ in a string and get the index.int index = str.indexOf( 'd');Example Live Demopublic class Demo { public static void main(String []args) { String str = "testdemo"; System.out.println("String: "+str); int index = str.indexOf( 'd' ); System.out.printf("'d' is at index %d, index); } }OutputString: testdemo 'd' is at index 4Let us see another example. The method returns -1, if the character isn’t found −Example Live Demopublic class ... Read More

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Let’s say the following is our string with special characters.String str = "test*$demo";Check for the special characters.Pattern pattern = Pattern.compile("[^A-Za-z0-9]"); Matcher match = pattern.matcher(str); boolean val = match.find();Now, if the bool value “val” is true, that would mean the special characters are in the string.if (val == true) System.out.println("Special characters are in the string.");Example Live Demoimport java.util.regex.Matcher; import java.util.regex.Pattern; public class Demo { public static void main(String []args) { String str = "test*$demo"; System.out.println("String: "+str); Pattern pattern = Pattern.compile("[^A-Za-z0-9]"); Matcher match = pattern.matcher(str); boolean val ... Read More