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You can use $match. The $match filters the documents to pass only the documents that match the specified condition to the next pipeline stage. Let us create a collection with documents −> db.demo629.insertOne( ... { ... ... "Subject": [ ... "MySQL", ... "MongoDB" ... ], ... "details": [ ... { ... Name:"Chris", ... "Marks":78 ... }, ... { ... Read More
To query for values in list, use positional operator($) in MongoDB. Let us create a collection with documents −> db.demo628.insertOne({id:1, Name:["Chris", "David", "John"]}); { "acknowledged" : true, "insertedId" : ObjectId("5e9ae7ea6c954c74be91e6b6") } > db.demo628.insertOne({id:1, Name:["Carol", "Sam"]}); { "acknowledged" : true, "insertedId" : ObjectId("5e9ae7f26c954c74be91e6b7") } > db.demo628.insertOne({id:2, Name:["Mike", "Sam", "John"]}); { "acknowledged" : true, "insertedId" : ObjectId("5e9ae8056c954c74be91e6b8") }Display all documents from a collection with the help of find() method −> db.demo628.find();This will produce the following output −{ "_id" : ObjectId("5e9ae7ea6c954c74be91e6b6"), "id" : 1, "Name" : [ "Chris", "David", "John" ] } { "_id" : ObjectId("5e9ae7f26c954c74be91e6b7"), "id" ... Read More
For this, use aggregate() along with $group. Let us create a collection with documents −> db.demo627.insertOne({id:101, "Name":"Chris", "Marks":54}); { "acknowledged" : true, "insertedId" : ObjectId("5e9acb306c954c74be91e6b2") } > db.demo627.insertOne({id:102, "Name":"Bob", "Marks":74}); { "acknowledged" : true, "insertedId" : ObjectId("5e9acb3c6c954c74be91e6b3") } > db.demo627.insertOne({id:101, "Name":"Chris", "Marks":87}); { "acknowledged" : true, "insertedId" : ObjectId("5e9acb426c954c74be91e6b4") } > db.demo627.insertOne({id:102, "Name":"Mike", "Marks":70}); { "acknowledged" : true, "insertedId" : ObjectId("5e9acb4b6c954c74be91e6b5") }Display all documents from a collection with the help of find() method −> db.demo627.find();This will produce the following output −{ "_id" : ObjectId("5e9acb306c954c74be91e6b2"), "id" : 101, "Name" : "Chris", "Marks" : ... Read More
For array interection in MongoDB, use the $setIntersection in aggregate(). Let us create a collection with documents −> db.demo625.insertOne( ... { ... Name: "John", ... Marks: [56, 98, 60] ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5e9ab8e16c954c74be91e6aa") } > db.demo625.insertOne( ... { ... Name: "John", ... Marks: [110, 56, 72] ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5e9ab8e26c954c74be91e6ab") } > db.demo625.insertOne( ... { ... Name: "Chris", ... ... Read More
Yes, you can use ensureIndex(). MongoDB provides complete support for indexes on any field in a collection of documents.Let us create a collection with documents −> db.demo622.ensureIndex({_id:1, Name:1, Age:1}); { "createdCollectionAutomatically" : true, "numIndexesBefore" : 1, "numIndexesAfter" : 2, "ok" : 1 } > db.demo622.insertOne({_id:101, Name:"Chris", Age:21}); { "acknowledged" : true, "insertedId" : 101 } > db.demo622.insertOne({_id:102, Name:"Chris", Age:22}); { "acknowledged" : true, "insertedId" : 102 } > db.demo622.insertOne({_id:103, Name:"Bob", Age:21}); { "acknowledged" : true, "insertedId" : 103 } > db.demo622.insertOne({_id:104, Name:"Chris", Age:22}); { "acknowledged" : true, "insertedId" : 104 } > db.demo622.insertOne({_id:104, Name:"Chris", Age:22}); 2020-04-18T12:21:18.085+0530 ... Read More
To aggregate second element from input element, use mapReduce(). Map-reduce is a data processing paradigm for condensing large volumes of data into useful aggregated results. Let us create a collection with documents −> db.demo621.insert({ _id: 101, Name1: "John", Name2: "John" }); WriteResult({ "nInserted" : 1 }) > db.demo621.insert({ _id: 102, Name1: "Bob", Name2: "John" }); WriteResult({ "nInserted" : 1 }) > db.demo621.insert({ _id: 103, Name1: "Chris", Name2: "John" }); WriteResult({ "nInserted" : 1 }) > db.demo621.insert({ _id: 104, Name1: "Sam", Name2: "John" }); WriteResult({ "nInserted" : 1 })Display all documents from a collection with the help of find() method −> ... Read More
Aggregation operations group values from multiple documents together, and can perform a variety of operations on the grouped data to return a single result.To aggregate in MongoDB, use aggregate(). Let us create a collection with documents −> db.demo620.insertOne({"Country":"IND", "City":"Delhi", state:"Delhi"}); { "acknowledged" : true, "insertedId" : ObjectId("5e9a8de96c954c74be91e6a1") } > db.demo620.insertOne({"Country":"IND", "City":"Bangalore", state:"Karnataka"}); { "acknowledged" : true, "insertedId" : ObjectId("5e9a8e336c954c74be91e6a3") } > db.demo620.insertOne({"Country":"IND", "City":"Mumbai", state:"Maharashtra"}); { "acknowledged" : true, "insertedId" : ObjectId("5e9a8e636c954c74be91e6a4") }Display all documents from a collection with the help of find() method −> db.demo620.find();This will produce the following output −{ "_id" : ObjectId("5e9a8de96c954c74be91e6a1"), ... Read More
Yes, we can do that using the NumberLong() datatype in MongoDB. Let us create a collection with documents −> db.demo618.insertOne({_id:NumberLong("6336366454"), Name:"Chris"}); { "acknowledged" : true, "insertedId" : NumberLong("6336366454") } > db.demo618.insertOne({_id:NumberLong("6336366455"), Name:"David"}); { "acknowledged" : true, "insertedId" : NumberLong("6336366455") } > db.demo618.insertOne({_id:NumberLong("6336366456"), Name:"Bob"}); { "acknowledged" : true, "insertedId" : NumberLong("6336366456") }Display all documents from a collection with the help of find() method −> db.demo618.find();This will produce the following output −{ "_id" : NumberLong("6336366454"), "Name" : "Chris" } { "_id" : NumberLong("6336366455"), "Name" : "David" } { "_id" : NumberLong("6336366456"), "Name" : "Bob" }Following is the query to implement MongoDB findOne() ... Read More
For this, use dot notation along with $group in MongoDB. Let us create a collection with documents −> db.demo617.insertOne( ... { ... ... "clientDetails": { ... "Name": "Chris", ... "Age":32, ... "Project":"Online Library Management System" ... } ... } ... ); { "acknowledged" : true, "insertedId" : ObjectId("5e99d2b86c954c74be91e69b") } > > db.demo617.insertOne( ... { ... ... "clientDetails": { ... "Name": "David", ... "Age":34, ... ... Read More
In MongoDB aggregate(), use $group and aggregate collection. Let us create a collection with documents −> db.demo616.insertOne({"details":{"Name":"Chris", "Age":21}}); { "acknowledged" : true, "insertedId" : ObjectId("5e99bfac65492f6c60d00283") } > db.demo616.insertOne({"details":{"Name":"Chris", "Age":22}}); { "acknowledged" : true, "insertedId" : ObjectId("5e99bfb065492f6c60d00284") } > db.demo616.insertOne({"details":{"Name":"Bob", "Age":23}}); { "acknowledged" : true, "insertedId" : ObjectId("5e99bfb865492f6c60d00285") } > db.demo616.insertOne({"details":{"Name":"Sam", "Age":21}}); { "acknowledged" : true, "insertedId" : ObjectId("5e99bfbd65492f6c60d00286") } > db.demo616.insertOne({"details":{"Name":"Chris", "Age":24}}); { "acknowledged" : true, "insertedId" : ObjectId("5e99bfc165492f6c60d00287") }Display all documents from a collection with the help of find() method −> db.demo616.find();This will produce the following output −{ "_id" ... Read More