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Suppose we have a string s, we have to make this string palindrome. in each step we can insert any character at any position, we have to find minimum number of characters that require to make this palindrome. If the string is like “mad”, then the answer will be 2 as we can add “da” before “mad”, or “am” after “mad” to make this palindrome.To solve this, we will follow these steps −Define a function lcs(), this will take s, x := sn := size of sreverse the string xs := concatenate space before s, x := concatenate space before ... Read More
Suppose we have a m x n binary matrix mat. In one step, we can choose one cell and flip its bit and all the four neighbors of it if they are present. We have to find the minimum number of steps required to convert mat to a zero matrix. If there is no solution, then return -1.So if the given input is like [[0, 0], [0, 1]], alteration will be like −So we need 3 steps, the output will be 3.To solve this, we will follow these steps −n := number of rows, m := number of columns, x ... Read More
Suppose we have a string s that is containing lowercase letters and an integer k. We have to maintain some properties. These are −First, we have to change some characters (if needed) of s to other lowercase English letters.Then divide the string s into k substrings such that each substring is a palindrome.We have to find the minimal number of characters that we need to change to divide the string.So if the string is like “ababbc” and k = 2, then the answer will be 1, as we have to change one character to split this into two palindrome strings. ... Read More
Suppose we have a car, that starts at position 0 and speed +1 on an infinite number line. The car runs automatically according to a sequence of instructions A: for accelerate and R − for reverse. When we get an instruction "A", our car does the following −position := position + speed, then speed = speed * 2.When we get an instruction "R", our car does the following −if speed is positive then speed = -1, otherwise speed = 1.For example, after executing the instructions "AAR", our car goes to positions 0->1->3->3, and speed goes to 1->2->4->-1.Now suppose we have ... Read More
Suppose we have a list of bus routes. In each routes[i] there is a bus route that the i-th bus repeats forever. So, if routes[0] = [1, 5, 7], this means that the first bus (0-th indexed) travels in the sequence 1, 5, 7, 1, 5, 7, 1, ... forever.Now suppose we start at bus stop S, initially not on a bus, and we want to go to bus stop T. we have to find the least number of buses we must take to reach our destination? If this is not possible then return -1.So if the input is like ... Read More
In this tutorial, we will be discussing a program to find the area of an Ellipse.For this, we will be provided with the semi-major axis and semi-minor axis of the Ellipse. Our task is to calculate and print out the area of the given Ellipse.Example Live Demo#include using namespace std; //finding area of ellipse void findArea( float a, float b) { float Area; Area = 3.142 * a * b ; cout
Suppose we have an array called nums, where nums[i] are written on a chalkboard. Ram and Sam take turns erasing exactly one element from the chalkboard, with Ram starting first. If erasing a number causes the bitwise XOR of all the elements of the chalkboard to become 0, then that player loses. Bitwise XOR of one element is that element itself, and the bitwise XOR of no elements is 0. If any player starts their turn with the bitwise XOR of all the elements of the chalkboard equal to 0, then that player will win. Suppose the array is holding ... Read More
Suppose we have one array A, we must move every element of A to either list B or list C. (These lists B and C are initially empty.) We have to check whether after such a move, it is possible that the average value of B is equal to the average value of C, and B and C are both non-empty.So if the input is like − [1, 2, 3, 4, 5, 6, 7, 8, 9, 10], then the result will be true, To solve this, we will follow these steps −n := size of A, total := 0for initialize ... Read More
Suppose we have an array A, we may rotate it by a K so that the array becomes A[K], A[K+1], A{K+2], ... A[A.length - 1], A[0], A[1], ..., A[K-1]. Then, any entries that are less than or equal to their index are worth 1 point.So for example, let we have an array [2, 4, 1, 3, 0], and we rotate by K = 2, it becomes [1, 3, 0, 2, 4]. This is worth 3 points because 1 > 0 [gain no point], 3 > 1 [gain no point], 0
Suppose we have a function f(x), this will return the number of zeroes at the end of factorial of x. So for f(3) = 0 because 3! = 6 has no zeroes at the end, while f(11) = 2 because 11! = 39916800 has 2 zeroes at the end. Now when we have K, we have to find how many non-negative integers x have the property that f(x) = K.So if the input is like K = 2, then the answer will be 5.To solve this, we will follow these steps −Define a function ok(), this will take x,ret := 0for initialize i := 5, when i